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kipiarov [429]
3 years ago
13

PLEASE HELP!

Mathematics
1 answer:
NARA [144]3 years ago
5 0
<span>Multiply the 1st equation by 5 and multiply the 2nd equation by 2. This will eliminate the x's when you add the two new equations together.
</span>
<span>A) −2x+3y=8
B) 5x+4y=10
So we multiply A) by 5 and B) by 2

</span><span>A) −10x+15y=40
B) 10x+8y=20
</span>
Adding the equations:
23y = 60
y = <span> <span> <span> 2.6086956522 </span> </span> </span>

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Edgar jarred 12 liters of jam after 2 days. How many days does Edgar need to spend making
S_A_V [24]

Answer:

3 days

Step-by-step explanation:

12 / 2 is 6 which is the unit rate

you do 18 / 6 to find how many days he needs to make it which will be 3 since in one day he can make 6 liters of jam

4 0
3 years ago
In the circle, m SRP = 5x+6 and m PQS = 9x+2. What is the value of x?
timurjin [86]
5x+6 + 9x+2=360
5x+9x= 360-6-2
14x÷14=352÷14
x=25.14
5 0
4 years ago
PLEASE HELP ASAP Which of the following is not a possible value of x?
scoundrel [369]
A is not a possible value.

B-D make more sense than A.
5 0
4 years ago
Read 2 more answers
What is the value of the expression???
Novosadov [1.4K]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to
djverab [1.8K]

This question is not complete, the complete question is;

Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to indicate whether their overall experience at Clarkson fell short of expectations, met expectations, or surpassed expectations. The results showed that 5% of the respondents did not provide a response, 26% said that their experience fell short of expectations, and 65% of the respondents said that their experience met expectations. Round your answers to two decimal places.

a. If we chose an alumnus at random, what is the probability that the alumnus would say their experience surpassed expectations

b. If we chose an alumnus at random, what is the probability that the alumnus would say their experience met or surpassed expectations?

Answer:

a) 0.04

b) 0.69

Step-by-step explanation:    

Given that

P ( No response ) = 5% = 0.05

P ( Short of expectation ) = 26 = 0.26

P ( Met expectation ) = 65% = 0.65

a)  the probability that the alumnus would say their experience surpassed expectations

P ( surpassed expectations) = 1 -  (P(No resp )+P( Short of exp)+ P( Met exp))

= 1 - (0.05 + 0.26 + 0.65 )

= 1 - 0.96

= 0.04

b) the probability that the alumnus would say their experience met or surpassed expectations.

the probability that  experience met or surpassed expectations is;

= P (met exp) + P ( surpassed exp)

= 0.65 + 0.04

= 0.69

 

5 0
3 years ago
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