Evaluate 12 sigma n=3 20(0.5)^n-1
9.99
19.95
29.98
39.96
2 answers:
Answer:
We have a geometric series in which:
a = 20
r = 1/2
Now, we know that: S2 = 20(1-r^2)/(1-r) and S12 = 20(1-r^12)/1-r
Therefore: sigma(3,12) = S12-S2 = 20[(1-r^12)/(1-r) - (1-r^2)/(1-r)] =5115/512 = 9.99023438
Therefore, the answer is: 9.99
Answer: Is D
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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the answer to the question is option A
to solve a problem like this, let x represent the first number
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Answer:
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Step-by-step explanation:
