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Georgia [21]
3 years ago
10

Evaluate 12 sigma n=3 20(0.5)^n-1 9.99 19.95 29.98 39.96

Mathematics
2 answers:
posledela3 years ago
3 0

Answer:

We have a geometric series in which:

a = 20

r = 1/2

Now, we know that: S2 = 20(1-r^2)/(1-r)  and S12 = 20(1-r^12)/1-r

Therefore:  sigma(3,12) = S12-S2  = 20[(1-r^12)/(1-r) - (1-r^2)/(1-r)]  =5115/512  = 9.99023438

Therefore, the answer is: 9.99

Ilya [14]3 years ago
3 0

Answer: Is D

Step-by-step explanation:

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