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makvit [3.9K]
3 years ago
5

I really need help and I'm really struggling

Mathematics
1 answer:
larisa [96]3 years ago
6 0
Firstly you can do 8 x 41 = 328.
Then 6 x 19 = 114,
114 + 328 = 442^2.

Hope this helps.
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Who can help me 10, 11, 12, 13,and 14
NeTakaya
11: 6(3x+4y)
13a: 5x(3-4y)
13b: they but “x” next to 4 when the expression didn’t have the “x^2” anywhere
14a: find the common factors of each number
8 0
4 years ago
Solve the inequality 4(k − 5) + 12k ≥ −4
IgorC [24]

Answer:

k ≥ 1

Step-by-step explanation:

Step 1: Write inequality

4(k - 5) + 12k ≥ -4

Step 2: Solve for <em>k</em>

  1. Distribute 4: 4k - 20 + 12k ≥ -4
  2. Combine like terms: 16k - 20 ≥ -4
  3. Add 20 to both sides: 16k ≥ 16
  4. Divide 16 on both sides: k ≥ 1
5 0
3 years ago
Read 2 more answers
Solve for d.<br> D + 6 &lt; 7
Lorico [155]

Answer: D<1

Step-by-step explanation:

Move all terms not containing D to the right side of the inequality.

Inequality Form:

D<1

3 0
3 years ago
First person to help gets brainliest
lions [1.4K]

The solution of the given equation w.r.t m is m = 3 ,i.e., option A

<h3>What are Algebraic equations?</h3>

With one exception, algebraic equations are essentially algebraic expressions.

An = sign is required in all algebraic equations.

No matter what kind of equation it is, all equations use the = sign.

The next topic is algebraic expression, which lacks the operators =,,, >, and.

To put it simply, there is no comparison between two terms in an algebraic statement.

Algebraic expressions frequently use terms like polynomial and square root.

So you now recognize the distinction between the two?

1) An algebraic equation has the symbol =, and 2) an algebraic expression lacks any comparison symbols (such as > and =).

As per the question:

6\frac{1}{9} + 3\frac{1}{3} =28\frac{1}{3}

55/9 + 10/3 = 85/3

(55m+30m)/9 = 85/3

85m/9 = 85/3

85m = (85*9)/3

85m = 85*3

m = (85*3)/85

∴ m = 3

To now more about algebraic equations, visit

brainly.com/question/953809

#SPJ13

5 0
1 year ago
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
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