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4 years ago

I NEED HELP!!!!!!!!!!!!!!!

Mathematics

1 answer:

Goshia [24]4 years ago

5 0

For part a, just add all segments of the race up

$3.8+179.2+42=225$ km

for part b, we are told that 1 mile is 1.6 km so
225

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Which fraction is greater 31/52 or 37/64

fiasKO [112]

31/52 is greater because the pie as I imagine it would be cut into bigger slices than 37/64 because then the pie has to be cut into 64 pieces instead of 52

Therefore, 31/52 is bigger and greater

6 0

4 years ago

(2x-3y)(4x+6xy) please help me solve this maths problem

sweet [91]

Answer:

8x^2+12x^2y−12yx−18y^2x

Step-by-step explanation:

was this the kind of answer you were looking for?

hope this helps :))

4 0

3 years ago

Read 2 more answers

I need help with this math. Max points!

pantera1 [17]

Take your previous answer and multiply it by 4.5!

5 0

3 years ago

For the function f x equals square root x ^ 3 - x, State the condition that must be satisfied for the FX to be Define. Then, sol

Svetradugi [14.3K]

Answer:

Domain: $[-1,0]\cup [1,\infty )$

Step-by-step explanation:

Since we know that a square root function is not defined for negative numbers. In order our function to be defined values inside radical must be greater than or equal to zero.

Our function will be defined when $x^{3} -x\geq 0$

$x(x^{2} -1)\geq 0$

$x(x-1)(x+1)\geq 0$

$1\geq x\leq 0$ or $x\geq1$

Now we will use number line method of solving inequalities to check whether our answer is right or not.

Let us try -2, -1/2, 1/2 and 2 to check which conditions meet our criteria.

$-2^{3} --2\geq 0\\-6\leq 0$

$(\frac{-1 }{2}) ^{3} -(\frac{-1}{2}) \geq0$

$\frac{-1}{8} +\frac{1}{2} \geq 0\\\frac{3}{8} \geq 0$

$(\frac{1 }{2}) ^{3} -\frac{1}{2} \geq0$

$\frac{1}{8} -\frac{4}{8} \leq 0$

$2^{3} -2\geq 0\\6\geq 0$

Therefore, we can see that our function is defined when $1\geq x\leq 0$ or $x\geq1$ and domain of f(x) is $[-1,0]\cup [1,\infty )$ .

4 0

3 years ago

Math question down below

Kipish [7]

Answer: 6928

----------------------------------------------------------

Explanation:

We have two areas we need to find: The area of the trapezoid and the area of the rectangle. Let's call these areas A1 and A2.

Area of Trapezoid = (height)*(base1+base2)/2
A1 = h*(b1+b2)/2
A1 = 80*(150+100)/2
A1 = 80*250/2
A1 = 20000
A1 = 10000

Area of Rectangle = (length)*(width)
A2 = L*W
A2 = 48*64
A2 = 3072

Subtract the two areas (A1-A2) to get the difference D
D = A1 - A2
D = 10000 - 3072
D = 6928

This difference D is exactly equal to the shaded area.

3 0

3 years ago