Answers:
- x = 7
- Area of shaded region = 162 square units
You may need to leave off the "square units" portion.
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Explanation:
For now, ignore the smaller rectangle and its dimensions. The larger rectangle has sides 3x and x+5, which I'll call the length and width.
L = 3x
W = x+5
The perimeter of any rectangle is P = 2(L+W). Plug in those values of L and W, and also the given perimeter P = 66. Isolate x.
P = 2(L+W)
2(L+W) = P
2(3x+x+5) = 66
2(4x+5) = 66
8x+10 = 66
8x = 66-10
8x = 56
x = 56/8
x = 7
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Now that we know x, we can find the area of the rectangles.
As you probably can guess, the shaded region is the difference of the two areas.
A = area of larger rectangle
A = (length)*(width)
A = (3x)*(x+5)
A = (3*7)*(7+5)
A = 252
B = area of smaller rectangle
B = (x+3)*(x+2)
B = (7+3)*(7+2)
B = 90
C = area of shaded region
C = A - B
C = 252 - 90
C = 162 square units is the area of the shaded region.
Step-by-step explanation:
y=kx
say that y is the original prince and x is the sale price
15=k(10)
15/10=k
3/2=k
you can check with the next problem to check if it is the same
25=k(20)
25/20=k
5/4=k
so you take 5/4-3/2=-1/4 so the constant is -1/4
Hope that helps :)
Answer:
it's just 8/20 so shade 8/20 of the circle
B. because it has three different terms
(if that makes sense)
Answer: 63.59cm²
Step-by-step explanation:
The area covered by the pitch will be gotten by finding the value of the area of the circle and this will be:
Area of q circle = πr²
where,
π = 3.14
r = radius = diameter/2 = 9cm/2 = 4.5cm
Area = πr² = 3.14 × 4.5²
= 3.14 × 20.25
= 63.59cm²
Therefore, the area covered by the pitch is 63.59cm²