The answer is 254. You want 299 with 15% off
Answer-
1. 3(2) + 5=6+5 = 11
2. 4(3) - 7 =12-7= 5
3. 2(3) - 4 =6-4 = 2
4. 6(4) - 2(3) =24-6 = 18
5. 2+3-4+5 = 5-4+5= 1+5 = 6
6. 7(4) - 2(2) = 28-4= 24
7. 2(3)(4) + 1 = 24+1 = 25
8. 2(3)(4) - 4 = 24-4 = 20
9. 8(2) /4 = 16/4 = 4
10. 6(3)/2 =18/2 = 9
11. 4(2) + 7 = 8+7 = 15
12. 2(4) - 7 = 8-7 = 1
13. 2(3) + 3(2) = 6+6 = 12
14. 6(2) - 1 = 12-1 = 11
15. 3(4) - 2 = 12-2 = 10
Factor the equation:
(x-7)(x+4)
Solve for X:
X-7=0 x+4=0
X=7 x=-4
A zero is when the function crosses the x-axis which is solved by setting the function equal to zero.
<span>It is best to rewrite the expression using addition before identifying the terms because when you have subtraction figures, those would make a term negative. As a result, it would be easier to accidentally misinterpret a term that is negative as positive when evaluating an expression. Rewriting it using addition would put the negative terms in parenthesis and make it easier to transpose those terms and ensure correct identification and use.</span>
Answer:
F(x=11)= (-31)
Step-by-step explanation:
for the function
F(x) = x² - 13*x + 22/x-11 , for x ≠ 11
then in order to define F(x=11) so F is continuous (see Note below) . By definition of continuity of a function:
F(x) is continuous in x=11 if lim F(x)=F(a) when x→a
then
when x→a , lim x² - 13x + 22/x-11 = lim 11² - 13*11 + 22/11 -11 = -3*11 + 2 = -31 = F(x=11)
then
F(x=11)= (-31)
Note:
F is not continuous in all x since
when x→0⁺ , lim (0⁺) ² - 13*0⁺ + 22/0⁺ -11 = (+∞)
when x→0⁻, lim (0⁻) ² - 13*0⁻ + 22/0⁻ -11 = (-∞)
then
limit F(x) , when x→0 does not exist since the limit from the left and from the right do not converge → since the limit does not exist , the function is not continuous in x=0
