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VLD [36.1K]
3 years ago
15

To mix his special energy drink, Jerome uses 8 cups of water and 3 cups of drink mix.

Mathematics
1 answer:
Serga [27]3 years ago
8 0
Jerome needs 336 cups of water and 126 cups of drink mix
You might be interested in
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6

\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
5 0
2 years ago
Transparency and worksheet master lesson 4.2 page 166
arlik [135]
Http://mrdealy.weebly.com/uploads/2/3/5/2/23520438/geom._ch._3_angle_diagrams__3.8_worksheet.pdf
3 0
3 years ago
Simplify the expression<br> 26 · 268
Gre4nikov [31]

Answer:

26 * 26^8 = 5.4295037e+12.

Step-by-step explanation:

26^8 = 208,827,064,576.\\26 * 208,827,064,576 = 5.42950373e+12.

hope this helps.

6 0
2 years ago
Help pleaseee i dont have many pts but ill mark brainliest​
eimsori [14]
You didn’t give the answers
6 0
3 years ago
A guy-wire extends from the top of a cell phone tower to a point on the
Fed [463]

Answer:

79.1 ft

Step-by-step explanation:

Draw a vertical segment about 3 inches tall. Label the upper endpoint A and the lower endpoint B. That is the cell phone tower. Starting at point B, draw a horizontal segment 1 inch long to the right. Label the right endpoint C. Connect C to A with a segment.

Segment BC is 25 ft long. Segment AB is 75 ft long. Angle B is a right angle.

You are looking for the length of segment AC, the guy wire length.

Triangle ABC is a right triangle with right angle B.

Sides AB and BC are the legs, and side AC is the hypotenuse.

We can use the Pythagorean Theorem:

(leg1)^2 + (leg2)^2 = (hyp)^2

Let one leg be a, the other leg be b, and let the hypotenuse be c.

Then you have

a^2 + b^2 = c^2

We have a = 75 ft

b = 25 ft

We are looking for c, the length of the hypotenuse.

(75 ft)^2 + (25 ft)^2 = c^2

5625 ft^2 + 625 ft^2 = c^2

6250 ft^2 = c^2

c^2 = 6250 ft^2

Take the square root of both sides.

c = 79.0569... ft

Answer: 79.1 ft

6 0
2 years ago
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