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Anna007 [38]
3 years ago
6

NEED HELP ASAP!!! Thank you

Mathematics
2 answers:
Illusion [34]3 years ago
8 0
  • 1/5+2/5= Z tgats tge way i think it is
Alla [95]3 years ago
4 0

Answer:

1/5+z= 3/5

Step-by-step explanation:

if z is in the down left corner and the fractions are ony in the upper part it means that is adding if z is in the down right corner it means that is subtracting but if there is one z and there is a numerous amount of cubes on the <u>right</u> that means is dividing. and i think if there is a z on the left and in the other side there is cubes that might be multiplying.

      Hope It Helps.

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3 3/4 x 4<br><br> Help me pas
alexandr1967 [171]
Convert any mixed numbers to fractions.
Then your initial equation becomes:

15
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Simplifying 60/4, the answer is
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4 0
2 years ago
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What would be the scientific notation of 10,200?
larisa86 [58]
It would be 1.02x10^4
7 0
3 years ago
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What is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1
aleksandr82 [10.1K]

Answer: 24

A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.

the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.

The general equation for the vertical hyperbola is

            [ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1

The conjugate axis of the vertical hyperbola is y = k

Length of the conjugate axis  = 2b

According to the question k = 2, h = -1, a = 4, b = 12

Length of the conjugate axis = 2b = 2 * 12  = 24

Learn more about hyperbola here :

brainly.com/question/3351710

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7 0
2 years ago
Over the weekend Ella ran three times as many miles as Vera. Together they ran 24 miles. How many miles did Vera run?
Butoxors [25]

answer is 72

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4 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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