Right side:
(1/27)^(2x+10)
=(3^-3)^(2x+10)
= 3^(-6x - 30)
Re-write both sides:
3^(4x-5) = 3^(-6x - 30)
from here, you can solve x
4x - 5 = -6x - 30
4x + 6x = -30 + 5
10x = -25
x = -2.5
A. (-) * (-) * (-) * (-) = positive
B. (-) * (-) * (-) = negative
C. (-) * (-) = positive
D. (-) * (-) * (-) = negative but times 0 = 0
so answer is
B. product will be negative
