A rigid transformation is
defined to be one in which the pre-image of the object and its new image after
the transformation both have the exact same size and shape. So the answer
in this question is:
<span>D. a circle's shape is preserved regardless of any rigid
transformation</span>
Answer:
2550yards
Step-by-step explanation:
Perimeter of a rectangle = 2L + 2W
L is the length
W is the width
If perimeter of a rectangle is 425 yards, then;
425 = 2L + 2W
425 = 2(L+W)
L+W = 425/2 .... 1
If the length and width of the rectangle are each multiplied by 6
P = 6(2L) + 2(2W)
P = 12L + 12W
P = 12(L+W) .... 2
Substitute 1 into 2
P = 12(425/2)
P = 6*425
P = 2550yd
Hence the perimeter of new triangle is 2550yards
Using the distance formula,


Since ABCD has two pairs of opposite congruent sides, it is a parallelogram.
It would be 6.01 so in other words B...
So first, you have to get two of the same variables to cancel out. Let's do this for x. In order for the x's to cancel out, we could multiply the bottom problem by 2.
(2) 3x-6y=24
After multiplying all the numbers by 2, you get the equation 6x-12y=48
The set of equations is now
-6x+2y=12
6x-12y=48
Now you can add them. The x variables cancel out, so you are left with the y variable.
2y+-12y=-10y and 12+48=60
Then you would divide 60 by -10 to get y=-6.
You would plug the answer for y into one of the original equations, lets do the top one. -6x+2y=12 becomes -6x+2(-6)=12
You'd multiply the 2 and -6 to get -12 so the equation is
-6x-12=12
The negative 12 turn positive and you add to both sides to get the -6x alone.
-6x-12=12
+12=12
-6x=24
Then divide 24 by -6
X=4
(-4,-6) is your final answer.