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AURORKA [14]
2 years ago
9

Ernesto buys a leaf blower price that $100 shipping and handling are an additional 10% of the price how much shipping and handli

ng will Ernesto pay ?​
Mathematics
1 answer:
Len [333]2 years ago
4 0
10% of 100 is 10 so 110
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When Sarah turned 18, she took $500 from her savings and opened a
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The worth of Sarah's investment when she is 68 is $14,728.51.

<h3>What is the worth of the investment?</h3>

The formula that can be used to determine the worth of the investment is:

FV = P (1 + r)^n

FV = Future value

P = Present value

R = interest rate

N = number of years = 68 - 18 = 50

$500 x (1.07)^50 = $14,728.51

To learn more about future value, please check: brainly.com/question/18760477

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For every arm a person has, they have a leg. Which ratio represents this situation?
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3/5x5/4 what the awnser? (HURRY PLZ I NEED HELP)
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Answer:

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Step-by-step explanation:

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In 2012, the population of a city was 6.29 million. The exponential growth rate was
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Answer:

  a) P(t) = 6.29e^(0.0241t)

  b) P(6) ≈ 7.3 million

  c) 10 years

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Step-by-step explanation:

a) You have written the equation.

  P(t) = 6.29·e^(0.0241·t)

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b) 2018 is 6 years after 2012.

  P(6) = 6.29·e^(0.0241·6) ≈ 7.2686 ≈ 7.3 . . . million

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c) We want t for ...

  8 = 6.29·e^(0.0241t)

  ln(8/6.29) = 0.0241t

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d) Along the same lines as the calculation in part (c), doubling time is ...

  t = ln(2)/0.0241 ≈ 28.7613 ≈ 28.8 . . . years

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2 years ago
The branch manager of a clothing store is analyzing the average total bill of sale for his location. the national manager has co
nadya68 [22]

Using the Central Limit Theorem, the branch manager can be 95% certain that the sample mean will fall within $1.034 of the mean.

<h3>What does the Central Limit Theorem state?</h3>

  • It states that the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.
  • By the Empirical Rule, 95% of the sample means fall within 2 standard errors of the mean.

In this problem, we have that the standard deviation and the sample size are given as follows:

\sigma = 10.34, n = 400

Hence the standard error is given by:

[tex]s = \frac{10.34}{\sqrt{400}} = 0.517.

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Hence, the branch manager can be 95% certain that the sample mean will fall within $1.034 of the mean.

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