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Tanya [424]
3 years ago
8

Using the values from the graph, compute the values for the terms given in the problem. Choose the correct answer. Age of car =

7 years. Original cost = $23,500. The cost of maintenance and repairs is $ .

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

Answer:

The cost of maintenance and repairs is $235

Step-by-step explanation:

step 1

Find the market values of car for age of car equal to 7 year

Observing the graph

The percentage of market value is 10%

so

10%=10/100=0.10

The market value is equal to

$23,500*0.10=$2,350

step 2

Find the cost of maintenance and repairs for age of car equal to 7 year

Observing the graph

The percentage of maintenance and repairs of car's value is 10%

so

10%=10/100=0.10

The cost of maintenance and repairs is

$2,350*0.10=$235

MariettaO [177]3 years ago
6 0

Answer:

$211.5

Step-by-step explanation:

Given information: Age of car = 7 years. Original cost = $23,500.

In the given graph it is clear that the solid line represents the percentage of market value of car and dashed line represents the maintenance and repair costs percentage of car's value.

From the given graph it is clear that, at age 7 year

Percentage of market value of car = 9%

Maintenance and repair costs percentage of car's value = 10%

At the age of 7 years, the value of car is 9% of original cost.

Value of car  = \frac{9}{100}\times 23,500=2115

The cost of maintenance and repairs is 10% of 2115.

The cost of maintenance and repairs = \frac{10}{100}\times 2115=211.5

Therefore, the cost of maintenance and repairs is $211.5.

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Step-by-step explanation:

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That is,

$ b_n \times 2^n + b_{n-1} 2^{n-1}+ ..... + b_02^0 $

$\therefore (1110 \ \ 0100 \ \ 0111 \ \ 1010)_2 $

=  $ (0 \times 2^0) + (1 \times 2^1) + (0 \times 2^2) + (1 \times 2^3) + (1 \times 2^4) + (1 \times 2^5) + (1 \times 2^6)  + ( 0 \times 2^7) + (0 \times 2^8) + (0 \times 2^9) + (1 \times 2^{10} ) $$  + (0 \times 2^{11}) + (0 \times 2^{12}) + (1 \times 2^{13}) + (1 \times 2^{14})+ (1 \times 2^{15})$

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The left most bit of the number represents the sign of the number. If bit = 1, the number is negative else if the bit is 0, the number is positive.

All the remaining bits (i.e all the bits except the leftmost bit) represent the magnitude of the number.

  Now, X = 1110 0100 0111 1010

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c).

Check the leftmost bit(lmb) of the number

if leftmost bit is 0 => convert do the binary to decimal conversion

if leftmost bit is 1, follow the following steps

  1. Flip the bits (convert the 0's into 1's and the vice versa)

  2. convert the new number from binary to decimal.

  3. Add a negative sign / multiply by -1

 Now, X = 1110 0100 0111 1010

left most bit = 1;

flipping the bits => Y = 0001 1011 1000 0101

converting Y into decimal => Y = 7045

multiplying Y with -1 => Y = -7045

Therefore, one's complement of X to decimal is -7045

Thus, X = -25722 in decimal.

d).

Check the leftmost bit(lmb) of the number

  if leftmost bit is 0 => convert do the binary to decimal conversion

  if leftmost bit is 1, follow the following steps

  1. Flip the bits (convert the 0's into 1's and the vice versa)

  2. convert the new number from binary to decimal.

  3. Add 1 to the converted number

  4. Add a negative sign / multiply by -1

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left most bit = 1;

flipping the bits => Y = 0001 1011 1000 0101

converting Y into decimal => Y = 7045

Adding 1 to Y => Y = 7046

multiplying Y with -1 => Y = -7046

Thus, two's complement of X to decimal is -7046

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