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3 years ago

A helicopter flew north 325 meters and then flew east 500 meters. How far is the helicopter from its starting point?

Mathematics

1 answer:

kati45 [8]3 years ago

8 0

Answer:

596.34m approx

Step-by-step explanation:

Given data

Let the Starting point be x

A helicopter flew north 325 meters from x

Then flew east 500 meters

Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position

x^2= 325^2+500^2

x^2=105625+250000

x^2= 355625

x= √355625

x=596.34m

Hence the distance from the starting point is 596.34m approx

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muminat

Answer:

21 and 26 totaling 47sticks

Step-by-step explanation:

Th number of sticks form an arithmetic progression

1, 6, 11, 16...

The nth term of an arithmetic progression is expressed as;

Tn = a+(n-1)d

a is the first term = 1

d is the common difference

d = 6-1 = 11-6 = 5

n is the number of terms

The next two terms are the fifth and sixth term

T5 = 1+(5-1)5

T5 = 1+4(5)

T5 = 1+20

T5 = 21

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Answer:

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Step-by-step explanation:

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3 years ago

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A bag contains only 50 cent coins and $1 bills. The total amount of money in the bag is $36. If there are twice as many 50 cents

vlabodo [156]

Answer:

The total number of 50 cent coins in the bag = 36.

Step-by-step explanation:

Let x be the number of 50 cents coins and y be the number of $1 bills.

We have been given that the total amount of money in the bag is $36. We can represent this information as:

$0.5x+y=36...(1)$

We are also told that there are twice as many 50 cents coins as $1 bills. We can represent this information as:

$x=2y...(2)$

Now we will use substitution method to solve our given system of equations. Upon substituting equation (2) in equation (1) we will get,

$0.5(2y)+y=36$

$y+y=36$

$2y=36$

$\frac{2y}{2}=\frac{36}{2}$

$y=18$

Now let us substitute y=18 in equation (2) to find our x.

$x=2*18$

$x=36$

Therefore, there are 36 fifty cent coins in the bag.

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