The perimeter of a rectangle is 400 yards what are the dimensions of the rectangle if the length is 40 yards more than the with
the length is how many yards and the width is how many yards
1 answer:
P = 2(L + W)
P = 400
L = W + 40
400 = 2(W + 40 + W)
400 = 2(2W + 40)
400 = 4W + 80
400 - 80 = 4W
320 = 4W
320/4 = W
80 = W.....so the width (W) = 80 yards
L = W + 40
L = 80 + 40
L = 120...and the length (L) = 120 yards
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