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velikii [3]
2 years ago
15

Please i need help with this question

Mathematics
1 answer:
topjm [15]2 years ago
4 0

Answer:

Ounces: 10, 15

Distance: 4, 6

Step-by-step explanation:

The ratio is constantly 5:2, which is equal to 10:4 and 15:6

You might be interested in
-5|4y-11|-3=12<br> Please answer with the steps
iren [92.7K]
-5║4y-11║-3=12
-5║4y-11║-3 +3=12+3
- 5║4y-11║=15
-5/5║4y-11║=15/-5
║4y-11║=-3

4y-11=-3 -5║4y-11║-3=12
4y-11+11=-3+11 -5║4(2)-11║-3=12
4y=8 -5║-3║-3=12
4y/4=8/4 -5 (3)-3=12
y=2 -18≠12

4y-11=3 -5║4y-11║-3=12
4y-11+11=3+11 -5║4(7/2)-11║-3=12
4y=14 -5(3)-3=12
4y/4=14/4 -18≠ 12
y=7/2

No solutions









3 0
3 years ago
What points in the scatter plot are outliers?
Julli [10]
X and h is the answer
3 0
3 years ago
Read 2 more answers
EMERGENCY HELP! A steady stream of water flows into a partially-filled rectangular tank. After 6 minutes, there are 87 gallons o
german

Answer:

y=9x+33

33 gallons of water to begin with.

Step-by-step explanation:

So we essentially are given two coordinates: (6,87) and (21,222). To find an equation, we simply need to find the slope and y-intercept. We know it's a linear equation because it's a steady stream, meaning a constant slope.

The slope is:

m=\frac{y_2-y_1}{x_2-x_1}=\frac{222-87}{21-6}=135/15=9

So, the rate at which the stream flows is 9 gallons per minute.

Now, let's find the initial amount of water. To do this, we can use point-slope form. Pick either of the two points. I'm going to use (6,87).

y-y_1=m(x-x_1)\\y-87=9(x-6)\\y-87=19-54\\y=9x+33

So, there were 33 gallons of water in the tank to begin with.

3 0
3 years ago
1) Your t-shirt provider sells you blank t-shirts for $5.00. What percent markup did you
Oksana_A [137]

Answer: 5%

Step-by-step explanation:

6 0
2 years ago
which of the following is the equation of the line that goes through the point (-4,-1) and has a slope of -3?
wel

Answer:

y = -3x - 11

Step-by-step explanation:

y - y1 = m(x-x1)

y - (-1) = -3(x-(-4))

y + 1 = -3(x+4)

y + 1 = -3x -12

y = -3x - 11

5 0
3 years ago
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