V=0.650 L
c=0.505 mol/L
M(Na₂CO₃)=106.0 g/mol
the amount of substance of sodium carbonate is:
n(Na₂CO₃)=vc
the mass of sodium carbonate is:
m(Na₂CO₃)=n(Na₂CO₃)M(Na₂CO₃)
m(Na₂CO₃)=vcM(Na₂CO₃)
m(Na₂CO₃)=0.650*0.505*106.0=34.7945 g
Answer:
23.0 s⁻¹ is rate constant
Explanation:
Using the Arrhenius equation:
k = A * e^(-Ea/RT)
Where k is rate constant
A is frequency factor (1.5x10¹¹s⁻¹)
Ea is activation energy = 55800J/mol
R is gas constant (8.314J/molK)
And T is absolute temperature (24°C + 273 = 297K)
Replacing:
k = 1.5x10¹¹s⁻¹ * e^(-55800J/mol/8.314J/molK*297K)
k = 1.5x10¹¹s⁻¹ * 1.53x10⁻¹⁰
k = 23.0 s⁻¹ is rate constant i hope this helpsss
Explanation:
<span>Answer:
mole of Cl- in 0.140 L of 0.25 M NH4Cl = 0.140 * 0.25
mole of Cl- in 0.380 L of 0.75 M CaCl2 = 0.380 * 0.75
Total = 0.140 * 0.25 + 0.380 * 0.75 = 0.32</span>
It depends on the concentration of ions which are responsible for the electrical conductivity in aqueous solutions.
Answer:
response I believe
Explanation:
i'm pretty sure it's a response cause it's the animal responding to needing water and being thirsty
hope this helps! :)