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Alla [95]
3 years ago
9

How many atoms are in 0.065 moles of Hg?

Chemistry
2 answers:
Sever21 [200]3 years ago
4 0
Formula: N=n x NA
=0.065 x 6.02 × 1023=
PolarNik [594]3 years ago
4 0

Answer: 3.91x10²² atoms Hg

Explanation: For a single mole of Hg it is equal to the Avogadro's Number or 6.022x10²³ atoms Hg.

0.065 mole Hg x 6.022x10²³ atoms Hg / 1 mole Hg

= 3.91x10²² atoms Hg

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Which is greater 50 degree celcius or 50 degree fahrenheit?with solution plz.....​
zheka24 [161]

Answer: 50 degrees Celsius is hotter than 50 degrees F. 50 degrees Celsius is half way between freezing and boiling

4 0
3 years ago
What is the theoretical yield of methanol (CH3OH) when 12.0 grams of H2 is mixed with 74.5 grams of CO? CO + 2H2 CH3OH
AlladinOne [14]
1) We need to convert 12.0 g of H2 into moles of H2, and <span> 74.5 grams of CO into moles of CO
</span><span>Molar mass of H2:    M(H2) = 2*1.0= 2.0 g/mol
Molar mass of CO:   M(CO) = 12.0 +16.0 = 28.0 g/mol

</span>12.0 g  H2 * 1 mol/2.0 g = 6.0 mol H2
74.5 g CO * 1 mol/28.0 g = 2.66 mol CO

<span>2) Now we can use reaction to find out what substance will react completely, and what will be leftover. 

                                  CO       +         2H2   ------->      CH3OH  
                                 1 mol              2 mol
given                        2.66 mol          6 mol (excess)

How much
we need  CO?           3 mol              6 mol

We see that H2 will be leftover, because for 6 moles H2  we need 3 moles CO, but we have only 2.66 mol  CO.
So, CO will react completely, and we are going to use CO to find  the mass of CH3OH.

3)                              </span>CO       +         2H2   ------->      CH3OH  
                                 1 mol                                        1 mol
                                2.66 mol                                    2.66 mol

4) We have 2.66 mol CH3OH
Molar mass CH3OH : M(CH3OH) = 12.0 +  4*1.0 + 16.0 = 32.0 g/mol

2.66 mol CH3OH * 32.0 g CH3OH/ 1 mol CH3OH =  85.12 g CH3OH
<span>
Answer is </span>D) 85.12 grams.
3 0
3 years ago
Which of the following is not equal to 42.7 millimeters?
Stella [2.4K]

The answer is: C. 0.00427 m.

A) 1 km = 1000000 mm.

d = 0.0000427 km · 1000000 mm/km.

d = 47.7 mm.

B) 1 hm = 100000 mm.

d = 0.000427 hm · 100000 mm/hm.

d = 42.7 mm.

C) 1 m = 1000 mm.

d = 0.00427 m · 1000 mm/m.

d = 4.27 mm.

D) 1 cm = 10 mm.

d = 4.27 cm · 10 mm/cm.

d = 42.7 mm.

Millimeter (abbreviated: mm, a thousandth part of metar) is an unit of distance in the metric system.

8 0
4 years ago
Is weathering long term or short term and why​
Marrrta [24]
Long term because if you leave something out to be weathered then it can’t be unweathered because of the drastic change of the object.
4 0
4 years ago
A sample of gaseous neon atoms at atmospheric pressure and 0 °c contains 2.69 * 1022 atoms per liter. the atomic radius of neon
omeli [17]

Explanation

Radius of neon atom : 69 pm = 69\times 10^{-12} m

Volume occupied by the one atom:\frac{4}{3}\pi r^3

=\frac{4}{3}\times 3.14\times(69\times 10^{-12} m)^3=1.37\times 10^{-30} m^3

given that 2.69\times 10^{22} atoms are present in 1L

1 L = 0.001 m^3

The volume occupied by the 2.69\times 10^{22} neon atoms

2.69\times 10^{22}\times 1.37\times 10^{-30} m^3=3.68\times 10^{-8} m^3

Fraction of volume occupied by the neon atom:

=\frac{3.68\times 10^{-8} m^3}{0.001 m^3}=3.68\times 10^{-11} m^3

3.68\times 10^{-11} m^3

The fraction of of volume occupied by the neon atom is very less than the 1 L which indicates the presence of large amount of empty space between the atoms of the gas.

3 0
3 years ago
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