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kolezko [41]
3 years ago
15

Between HClO3 and HIO3, which is stronger and why? Question 16 options: 1) HClO3 is stronger because chlorine is in a higher oxi

dation state than iodine. 2) HClO3 is stronger because chlorine is more electronegative than iodine. 3) HIO3 is stronger because iodine is in a higher oxidation state than chlorine. 4) HIO3 is stronger because iodine is less electronegative than chlorine.
Chemistry
1 answer:
natima [27]3 years ago
4 0

Answer:

2) HClO3 is stronger because chlorine is more electronegative than iodine.

Explanation:

The more electronegative the element is the more strong or acidic it becomes.

Chlorine being more electronegative than Iodine makes it easier for it to pull the electron of hydrogen more strongly and hence has a higher tendency to release a H+ unit. Hence that makes it stronger.

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fgiga [73]

Answer:

atomic number

Explanation:

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4 0
3 years ago
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And electro chemical cell has the following standard cell notation:
pochemuha

2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq)

<h3>Further explanation</h3>

Given

Standard cell notation:

Mg(s) | Mg2+ (aq) || Ag+(aq)| Ag(s)

Required

a balanced redox reaction

Solution

At the cathode the reduction reaction occurs, the anode oxidation reaction occurs

In reaction:  

Ag⁺ + Mg → Ag + Mg²⁺  

half-reactions

  • at the cathode (reduction reaction)

Ag⁺ (aq) + e⁻ ---> Ag (s)  x2

2Ag⁺ (aq) + 2e⁻ ---> 2Ag (s)

  • at the anode (oxidation reaction)

Mg (s) → Mg²⁺ (aq) + 2e−

a balanced cell reaction

<em>2Ag⁺(aq) + Mg(s)→ 2Ag(s) + Mg²⁺ (aq) </em>

5 0
3 years ago
Read 2 more answers
Find the mass, in grams, of 5.00*10^23 molecules of F2
Westkost [7]

Answer:   31.55 g

Explanation:

- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of         fluorine gas (F2) = 37.98 g/mol.

-  1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),

   so   1 mole of (F2) with 37.98 g/mol →  6.02×10^23 molecules.

- Using cross multiplication,  

                               37.98 g/mol of (F2)        →       6.02 ×10^23 molecules

                                                       ?              →        5.00 ×10^23 molecules

Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..


7 0
4 years ago
What is the standard potential, e∘celle∘cell, for this galvanic cell? use the given standard reduction potentials in your calcul
Olin [163]

The standard potential for the given galvanic cell is 0.477 V

<h3>What is electrode potential?</h3>

The electrode potential is the electromotive force of a galvanic cell built using a standard reference electrode and another electrode whose potential is to be found.

There are two types of electrode potential

Oxidation potential - The potential associated with oxidation reaction is known as oxidation potential

Reduction potential - The potential associated with reduction reaction is known as reduction potential

At the anode, oxidation occurs

Sn(s)\rightarrow Sn^{2+}(aq)+2e^-

At the cathode, reduction occurs

Cu^{2+}(aq)+2e^-\rightarrow Cu(s)

E^o_{cell} =E^o_{cathode} -E^o_{anode}

        = 0.337 - (-0.140)

        = 0.477 V

Thus, The standard potential for the given galvanic cell is 0.477 V

Learn more about electrode potential:

brainly.com/question/17362810

#SPJ4

Disclaimer: The question was given incomplete on the portal. Here is the complete question

Question: What is the standard potential, E∘cell, for this galvanic cell? Use the given standard reduction potentials in your calculation as appropriate.

Sn^{2+}(aq)+2e^-\rightarrow Sn(s), E°red=−0.140 V

Cu^{2+}(aq)+2e^-\rightarrow Cu(s), E°red=+0.337 V

4 0
2 years ago
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Mariulka [41]
The correct answer is 9 .
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3 years ago
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