**Answer:**

Volume of chlorine = 61.943 mL

**Explanation:**

Given:

Volume of the water in the Pool = 18,000 gal

also,

1 gal = 3785.412 mL

thus,

Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL

Density of water = 1.00 g/mL

Therefore,

The mass of water in the pool = Volume × Density

or

The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g

in terms of million =

or

= 68.13747 g

also,

1 g of chlorine is present per million grams of water

thus,

chlorine present is 68.13747 g

Now,

volume =

or

Volume of chlorine =

or

**Volume of chlorine = 61.943 mL**

**Answer:**

The first one is air the second is decreases the third is water the fourth is gas and the last is liquid.

**Explanation:**

Hope it helps.

**Answer:**

Chlorine

**Explanation:**

The P usually stands for Protons, and that is usually the element number. (chlorine is 17) N is for neutron

Hello!!! I would like to give you my answer!!!

<span>%error= (-890kJ-0.07kJ)/(-890kJ)x100 = 110.02%

I hope this helps!!! :-D</span>

Answer is: the percent by mass of NaHCO₃ is 2,43%.

m(NaHCO₃) = 10 g.

V(H₂O) = 400 ml.

d(H₂O) = 1 g/ml.

m(H₂O) = V(H₂O) · d(H₂O).

m(H₂O) = 400 ml · 1 g/ml.

m(H₂O) = 400 g.

m(solution) = m(H₂O) + m(NaHCO₃).

m(solution) = 400 g + 10 g.

m(solution) = 410 g.

ω(NaHCO₃) = 10 g ÷ 410 g · 100%.

ω(NaHCO₃) = 2,43 %