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faltersainse [42]
4 years ago
15

Which term is used to describe the reactant that is used up completely and controls the amount of product that can be produced d

uring a chemical reaction? Catalytic reactant Excess reactant Limiting reactant Theoretical reactant
Chemistry
1 answer:
givi [52]4 years ago
6 0

Answer: Option (c) is the correct answer.

Explanation:

A limiting reagent is defined as a reagent that completely gets consumed in a chemical reaction. A limiting reagent limits the formation of products.

For example, we have given 5 mol of A and the reaction is 2A + 4B \rightarrow 2AB

Whereas when 4 mol B will react with 2 mol of A. Hence, 8 mol of B will react with 4 mol A as follows.

                        \frac{2}{4} \times 8 = 4 mol

As, the given moles of A is more than the required moles. Thus, it is considered as an excess reagent.

Hence, B is a limiting reagent because it limits the formation of products.

Thus, we can conclude that limiting reactant is the term used to describe the reactant that is used up completely and controls the amount of product that can be produced during a chemical reaction.  

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Calculate the temperature, in k, of 2.20 moles of gas occupying 3.30 l at 3.50 atm.
Sergio [31]
From  idea  gas  equation  that is   PV=nRT
T= temperature  in kelvin
R=gas   cosntant(0.0821atm/k/mol)
P=pressure(3.5atm)
V=volume 3.30L
n=number  of  moles (2.20mole)
T  is  therefore  =PV/nR
T={(3.50 x3.30) /(2.20 x 0.0821)}=63.95k
3 0
4 years ago
Comets _____. orbit the Earth are usually found between Jupiter and Mars have very irregular shapes have very elliptical orbits
AURORKA [14]

Answer:

Asteroids???? idk and its not a guaranteed answer

7 0
4 years ago
Two elements next to each other that have decreasing atomic masses
pogonyaev

Answer:

  • <u>Tellurium (Te) and iodine (I) are two elements </u><em><u>next to each other that have decreasing atomic masses.</u></em>

Explanation:

The <em>atomic mass</em> of tellurium (Te) is 127.60 g/mol and the atomic mass of iodine (I) is 126.904 g/mol; so, in spite of iodine being to the right of tellurium in the periodic table (because the atomic number of iodine is bigger than the atomic number of tellurium), the atomic mass of iodine is less than the atomic mass of tellurium.

The elements are arranged in increasing order of atomic number in the periodic table.

The atomic number is equal to the number of protons and the mass number is the sum of the protons and neutrons.

The mass number, except for the mass defect, represents the atomic mass of a particular isotope. But the atomic mass of an element is the weighted average of the atomic masses of the different natural isotopes of the element.

Normally, as the atomic number increases, you find that the atomic mass increases, so most of the elements in the periodic table, which as said are arranged in icreasing atomic number order, match with increasing atomic masses. But the relative isotope abundaces of the elements can change that.

It is the case that the most common isotopes of tellurium have atomic masses 128 amu and 130 amu, whilst most common isotopes of iodine have an atomic mass 127 amu. As result, tellurium has an average atomic mass of 127.60 g/mol  whilst iodine has an average atomic mass of 126.904 g/mol.

5 0
3 years ago
If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol
Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity  :

v_{rms}=\sqrt{\frac{3RT}{M}}

K.E_{avg}=\frac{3}{2}RT

K.E =\frac{1}{2}mv_{rms}^{2}

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

K.E_{avg}=\frac{3}{2}RT

T=\frac{2(K.E)}{3(R)}

K.E of He = 4310 J/mol

T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}

T=345.60K

<u>Now , Use Vrms to calculate the velocity of O2</u>

v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}

v_{rms}=\sqrt{\frac{8619.9552}{0.032}}

v_{rms}=\sqrt{26935.001}

v_{rms}=519.01m/s

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Advantages of artificial silk over natural silk​
Serhud [2]

Answer:

Less expensive than natural fibers

Strong and long-lasting

Easily available

Easy to maintain

Dry up quickly

6 0
2 years ago
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