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Novosadov [1.4K]
3 years ago
15

If 8^y = 16^y+2, what is the value of y? A) -8 B) -4 C) -2 D) -1

Mathematics
1 answer:
Sonbull [250]3 years ago
5 0

For this case we have the following expression:

8 ^ y = 16^{ y + 2}

We know that:

8 = 2 * 2 * 2 = 2 ^ 3\\16 = 2 * 2 * 2 * 2 = 2 ^ 4

Rewriting the expression we have:

2^{ 3(y)} = 2^ {4 (y + 2)}\\2^{3y} = 2^{4y + 8}

For equality to be met we have to:

3y = 4y + 8\\3y-4y = 8\\-y = 8\\y = -8

ANswer:

The value of the variable "y" is -8.

Option A

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Read 2 more answers
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