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2 years ago

Area and perimeter of 9cm and 11cm

Mathematics

1 answer:

Law Incorporation [45]2 years ago

6 0

Answer: Area: 99cm Perimeter: 40cm

Step-by-step explanation:

To find the area, you would multiply 9cm by 11cm because the formula for area is length times width. To find the perimeter, you add all the sides, which would mean you add 9 + 9 + 11 + 11, making the perimeter 40cm.

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Step-by-step explanation:

220000/100=2200*0.49=789

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2 years ago

Which equation is the equivalent form of 20(3)^5x = 820?

makvit [3.9K]

Answer:

x=ln(41)/ln(243)

Step-by-step explanation:

20(3)^5x=820

3^5x=820/20

3^5x=41

5x=ln(41)/ln(3)

x=(1/5)[ln(41)/ln(3)]

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2 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

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