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3 years ago

PLEASE HELP ASAP!!!!!!! 20 POINTS

Mathematics

1 answer:

aliya0001 [1]3 years ago

6 0

Recall the compound interest formula
$a = p {(1 + \frac{r}{n} )}^{nt}$
Where r = 0.04, n = 12 since compounded monthly, t = 30, and p, initial value, is 24000.

Plug them in, 79523.95 seems to be the solution.

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A group of 10 students participate in chess club, karate club, or neither

oksano4ka [1.4K]

Answer:-0

Step-by-step explanation:

8 0

2 years ago

My victory will be in your hands if you answer this ✌✌✌✌✌

Julli [10]

Add dress and shoes together:

30 + 25 = 55

1/5 off means the total after discount would be 4/5 ( 1 - 1/5 = 4/5)

Multiply total price by 4/5:

55 x 4/5 = (55 x4)/5 = 220/5 = 44

Total after discount is 44

Now add shipping:

44 + 8 = 52

Total paid = £52

7 0

2 years ago

Read 2 more answers

What does this mean? evaluate the expression for y=54y+10

salantis [7]

We have the expression:

$4y+10$

And want to evaluate in y=5, this means we have to replace y in the expression for 5 and calculate the value of the expression, so:

$\begin{gathered} 4y+10,y=5 \\ 4\cdot5+10 \\ 20+10 \\ 30 \end{gathered}$

The expression is 30 when y=5.

7 0

1 year ago

Find the scale factor

Mama L [17]

Answer:

C. 50

Step-by-step explanation:

The triangles are proportional and that is why you can find the scale factor. Set up a proportion (equivalent fractions). Set the proportion up with the corresponding sides together on thee top or the bottom of the proportion.

65 = 91

x 70

91x = 65 * 70

91x = 4550

91 91

x = 50

8 0

2 years ago

Can someone please help me with my Question #29 of The Quadratic Relations for me please?

lara [203]

Answer:

Calculate the first differences between the y-values:

$\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19$

As the first differences are not the same, we need to calculate the second differences:

$\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7$

As the second differences are the same, the relationship between the variable is quadratic and will contain an $x^2$ term.

--------------------------------------------------------------------------------------------------

To determine the quadratic equation

The coefficient of $x^2$ is always half of the second difference.

As the second difference is 2, and half of 2 is 1, the coefficient of $x^2$ is 1.

The standard form of a quadratic equation is: $y=ax^2+bx+c$

(where a, b and c are constants to be found).

We have already determined that the coefficient of $x^2$ is 1.

Therefore, a = 1

From the given table, when $x=0$ , $y=12$ .

$\implies a(0)^2+b(0)+c=12$

$\implies c=12$

Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

$\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}$

Therefore, the quadratic equation for the given ordered pairs is:

$y=x^2+6x+12$

7 0

2 years ago