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Olenka [21]
3 years ago
6

Need help in algebra quick

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

A. 2•4^t

Step-by-step explanation:

To solve this problem, we plug in the x values for t and solve.

If you plug in x values for t and solve in Answer A, here is what you get:

2•4^1=2•4=8

2•4^2=2•16=32

2•4^3=2•64=128

2•4^4=2•256=512

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18
asambeis [7]

Answer:

B

Step-by-step explanation:

When we have a horizontal translation on the x-axis, it means the translation in question would be affecting only the x component of our function

With respect to the question, what we have here is that we are going to take out some values from x (or add some values) to it

Thus;

f(x) = x^2 would be;

g(x) = (x-4)^2

Corresponding to a shift to the right of upto 4 units on the x axis

7 0
3 years ago
Solve for x.<br><br> 12-3 =3x
Dmitry_Shevchenko [17]
12 minus three is 9. 9 divided by 3 is 3. so X is three

6 0
3 years ago
Read 2 more answers
Simplify. -y -7x + 7y<br> The simplified expression is ___y - ____x.
goblinko [34]

Answer:

the simplified expression is: 6y-7x

Step-by-step explanation:

-y+7y= 6y

           -7x

           = 6y-7x

8 0
3 years ago
Krystal buys a bag of cookies that contains 9 chocolate chip cookies, 7 peanut butter cookies, 7 sugar cookies and 7 oatmeal rai
d1i1m1o1n [39]

Answer:

7/145

Step-by-step explanation:

We have

9 chocolate chip cookies

7 peanut butter cookies

7 sugar cookies

7 oatmeal raisin cookies.

9+7+7+7 = 30 cookies.

What is the probability that Krystal randomly selects a peanut butter cookie from the bag, eats it, then randomly selects another peanut butter cookie?

Initially, there are 30 cookies, 7 of which are peanut butter cookies. So the probability that Krystal selects a peanut butter from the bag is 7/30.

Suppose she selected the peanut butter cookie. Now there are 29 cookies, of which 6 are peanut butter. So the probability that the second one is a peanut butter cookie is 6/29.

Probability that both are peanut butter cookies:

Multiplication

P = \frac{7}{30}\frac{6}{29} = \frac{7}{145}

5 0
3 years ago
A rectangular box is to have a square base and a volume of 72 ft3. If the material for the base costs $0.62/ft2, the material fo
Igoryamba

Answer:

a. length  = 0.7211 ft

b. width  = 0.7211 ft

c. height = 140.3846 ft

Step-by-step explanation:

This is an optimiztion with restriction problem.

We have to minimize the cost, with the restriction of the volume being equal to 72 ft3.

As the cost for the sides is constant, we know that length and width are equal.

Then, we can express the volume as:

V=x\cdot y\cdot z=x^2z=73

being x: length and z: height

We can express the height in function of the length as:

x^2z=73\\\\z=73x^{-2}

Then, the cost of the box can be expressed as:

C=0.62(x^2)+4*0.15(xz)+0.18(x^2)=(0.62+0.18)x^2+0.60xz\\\\C=0.8x^2+0.60x*x^{-2}=0.8x^2+0.6x^{-1}

To optimize C, we derive and equal to zero

\dfrac{dC}{dx}=\dfrac{d}{dx}[0.8x^2+0.6x^{-1}]=1.6x-0.6x^{-2}=0\\\\\\1.6x=0.6x^{-2}\\\\x^{1+2}=0.6/1.6=0.375\\\\x=\sqrt[3]{0.375} =0.7211

The height z is then

z=73x^{-2}=\dfrac{73}{0.7211^2}=\dfrac{73}{0.52}=140.3846

6 0
3 years ago
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