The area of one of the triangular lateral faces is

You're told that the slant height, which is the same as the height of the triangular face, is 9.8, so you have

where

is the length of the base of the triangle, which is also the same as the side length of the base of the pyramid. So
Did you already find the answer?
Answer: 6.5<6.55
Step-by-step explanation: Because you add the zero to the 6.50 but it’s still less than 6.55.
Answer:
lw +
× π ×
⇒ Answer D is correct
Step-by-step explanation:
First, let us find the area of the semi-circle.
Area =
× π × r²
<u>Given that,</u>
diameter of the semi-circle is ⇒ <em>l</em>
∴ radius ⇒ <em>l / 2</em>
<u>Let us find it now.</u>
Area =
× π × r²
Area =
× π × 
<u> </u>
Secondly, let us find the area of the rectangle.
Area = length × width
<u>Given that,</u>
length ⇒ <em>l</em>
width ⇒ w
<u>Let us find it now.</u>
Area = length × width
Area = l ×w
Area = lw
<u> </u>
And now let us <u>find the total area.</u>
Total area = Area of the rectangle + Area of the semi - circle
Tota area = lw +
× π × 