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2 years ago

Which of the following is required to construct the inscribed circle of a triangle?

Mathematics

2 answers:

Inessa [10]2 years ago

7 0

D incenter of a triangle

IceJOKER [234]2 years ago

5 0

Answer:

D. the incenter

Step-by-step explanation:

Because it is the "Correct Answer"

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Q1 Q2 - Using ratios Complete the table for this pattern. 8

Natalka [10]

POR N EASILY YDIPGIDILDGDIPDY

5 0

2 years ago

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.

Lina20 [59]

Answer:

$CD\approx0.2$

Step-by-step explanation:

By the tangent ratio, $tanC=\frac{DB}{CD}$ . Substituting the given values into this equation gives us:

$tan83$ ° $= \frac{1.3}{CD}$

$CD*tan83$ ° $=1.3$ (Multiply both sides of the equation by $CD$ )

$CD=\frac{1.3}{tan83\textdegree}$ (Divide both sides of the equation by $tan83\textdegree$ )

$CD=0.15962\approx0.2$

Hope this helps!

3 0

2 years ago

PLEASE HELP ME WITH THIS QUESTION ^^

AURORKA [14]

I’m sorry I don’t get that whole situation

4 0

2 years ago

Who can help me out with this question???

GaryK [48]

Answer:

x = 13

Step-by-step explanation:

$a^{2} +b^2 = c^2\\12^2 + 5^2 = c^2\\144 + 25 = c^2\\169 = c^2\\$

Take the square root of both sides

$\sqrt{169} = \sqrt{c^2} \\13 = c$

8 0

2 years ago

Is f(x) continuous at x equals 4? Why or why not? A. No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit

soldier1979 [14.2K]

Corrected Question

Is the function given by:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

continuous at x=4? Why or why not? Choose the correct answer below.

Answer:

(D) Yes, f(x) is continuous at x = 4 because $Lim_{x \to 4}f(x)=f(4)$

Step-by-step explanation:

Given the function:

$f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right$

A function to be continuous at some value c in its domain if the following condition holds:

f(c) exists and is defined.

$Lim_{x \to c}$ f(x)$ exists.

$f(c)=Lim_{x \to c}$ f(x)$

At x=4

$f(4)=\dfrac{1}{4}*4+1=2$

$Lim_{x \to 4}f(x)=2$

Therefore: $Lim_{x \to 4}f(x)=f(4)=2$

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0

2 years ago