Question

Help me fjfjsncjdhdhfh​

Answer 1

Step-by-step explanation:

$=> 2 {x}^{2} + \frac{7}{2}x + \frac{3}{4} = 0$

$=> \frac{8 {x}^{2} + 14x + 3}{4} = 0$

$=> 8 {x}^{2} + 14x + 3 = 0$

$=> 8 {x}^{2} + 12x + 2x + 3 = 0$

$=> 4x(2x + 3) + 1(2x + 3) = 0$

$= > (2x + 3)(4x + 1) = 0$

$= > x = - \frac{3}{2} or \frac{ - 1}{4}$

option C