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ddd [48]
4 years ago
9

A seafood company produces cans of tuna. Each can gets wrapped with a paper label. If every van has a radius of 8.3 centimeters,

what is the approximate length of the paper required to cover two cans?
Mathematics
2 answers:
Tanzania [10]4 years ago
7 0

Answer:

First, we should find out what the circumference of one can is and then multiply it by two, because they ask us about two cans.

The formula for calculating the circumference is:

C = 2πr

Good news - we have r! r equals 8.3 cm.

So the circumference of one can, hence length of one piece of paper, equals 2π * 8.3 = 16.6π. Length of two pieces of paper is the result of this multiplication: 2 * 16.6π = 33.2π

jok3333 [9.3K]4 years ago
6 0
First, we should find out what the circumference of one can is and then multiply it by two, because they ask us about two cans.

The formula for calculating the circumference is:
C = 2πr

Good news - we have r! r equals 8.3 cm.
So the circumference of one can, hence length of one piece of paper, equals 2π * 8.3 = 16.6π. Length of two pieces of paper is the result of this multiplication: 2 * 16.6π = 33.2π
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What’s the area of 7.4cm and 4.5cm
Vadim26 [7]

Answer:

33.3

Step-by-step explanation:

The formula for area is length*width.

7.4*4.5=33.3

5 0
3 years ago
Read 2 more answers
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0
3 years ago
12 years ago, Juan was 2/3 the age he is now. Write and solve an equation to figure out how old he is now.
astra-53 [7]
12 x 2/3= a. a being his current age. hope this is correct!
8 0
3 years ago
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during the lunch break a deli sold 36 large sodas. If the ratio of large sodas sold to small sodas sold was 4:1, how many small
FromTheMoon [43]
45 sodas total. To find the number of small sodas U would divide 36 by 4 and get 9. Then add 9 to 36.
8 0
4 years ago
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At which root does the graph of f(x) = (x + 4) 6(x + 7)5 cross the x-axis?<br> 0 -7<br> ООО
Maslowich

the root for which the graph of f(x) = (x+4)^{6}(x+7)^{5} cross the x-axis i.e. value of y or f(x) = 0 is x = -7  .

<u>Step-by-step explanation:</u>

We have , f(x) = (x + 4) 6(x + 7)5 i.e.f(x) = (x+4)^{6}(x+7)^{5}. We need to find root for which the graph of f(x) = (x+4)^{6}(x+7)^{5} cross the x-axis i.e. value of y or f(x) = 0. Let's solve this:

⇒ f(x) = (x+4)^{6}(x+7)^{5}

⇒ 0 = (x+4)^{6}(x+7)^{5}

⇒ (x+4)^{6}(x+7)^{5} = 0

Which means either x+4 = 0\\x = -4 or , x+7=0\\x=-7 . That means the root for which the graph of f(x) = (x+4)^{6}(x+7)^{5} cross the x-axis i.e. value of y or f(x) = 0 is x= -4 or x = -7 . ∴ From given options , the root for which the graph of f(x) = (x+4)^{6}(x+7)^{5} cross the x-axis i.e. value of y or f(x) = 0 is x = -7  .

3 0
4 years ago
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