I need help on everything

Mathematics

1 answer:

Irina-Kira [14]3 years ago

8 0

Answer sheet:

#10 Answer: 22* and 68* (* is the degrees sign)
b= 3c+2
4c+2=88
c=22 degrees

b=3(22)+2
=66+2
b= 68 degrees

You might be interested in

A price decreased from 60$ to 45$ find the percent of decrease

BlackZzzverrR [31]

Percent change = [(45 - 60) / 60] x 100 = -25 % (decrease)

8 0

3 years ago

Read 2 more answers

In the coordinate plane, the point X (3, 1) is translated to the point X'(4, -1). Under the same translation, the points Y(-1, -

torisob [31]

<h3>Answer:y and z</h3>

Step-by-step explanation:

<h2>bc y and z is in the alphabet </h2>

7 0

3 years ago

Y = (x)^(1/9)*Find f(x) when x=(1/2)Round your answer to the nearest thousandth.

Verizon [17]

We are given a function f ( x ) defined as follows:

$y=f(x)=x^{\frac{1}{9}}$

We are to determine the value of f ( x ) when,

$\times\text{ = }\frac{1}{2}$

In such cases, we plug in/substitue the given value of x into the expressed function f ( x ) as follows:

$y\text{ = f ( }\frac{1}{2}\text{ ) = (}\frac{1}{2})^{\frac{1}{9}}$

We will apply the power on both numerator and denominator as follows:

$f(\frac{1}{2})=\frac{1^{\frac{1}{9}}}{2^{\frac{1}{9}}}\text{ = }\frac{1}{2^{\frac{1}{9}}}$

Now we evaluate ( 2 ) raised to the power of ( 1 / 9 ).

$f\text{ ( }\frac{1}{2}\text{ ) = }\frac{1}{1.08005}$

Next apply the division operation as follows:

$f\text{ ( }\frac{1}{2})\text{ = }0.92587$

Once, we have evaluated the answer in decimal form ( 5 decimal places ). We will round off the answer to nearest thousandths.

Rounding off to nearest thousandth means we consider the thousandth decimal place ( 3rd ). Then we have the choice of either truncating the decimal places ( 4th and onwards ). The truncation only occurs when (4th decimal place) is < 5.

However, since the (4th decimal place) = 8 > 5. Then we add ( 1 ) to the 3rd decimal place and truncate the rest of the decimal places i.e ( 4th and onwards ).

The answer to f ( 1 / 2 ) to the nearest thousandth would be: