Step-by-step explanation:
vol =πr²h
22/7×8×8×3
= 603.2
<em>The</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>x^</em><em>2</em><em>-</em><em>1</em><em>.</em>
<em>EXPLANATION</em><em>:</em>
<em>To</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>polynomial</em><em>,</em><em> </em><em>the</em><em> </em><em>power</em><em> </em><em>of</em><em> </em><em>each</em><em> </em><em>term</em><em> </em><em>must</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>whole</em><em> </em><em>number</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
<em>~</em><em>p</em><em>r</em><em>a</em><em>g</em><em>y</em><em>a</em>
Answer:
2√6
Step-by-step explanation:
find the hypotenuse of the triangle thats 3 and 7
pythagorean
3 squared + 7 squared
16 + 49 = 57
√57 is the hypotenuse
√57 is also the base of the triangle that has side thats 9
pythagorean theorem
x squared + √57 squared = 9 squared
x^2 + 57 = 81
x^2 = 81 - 57
x^2 = 24
x = √24
x = √4 * √6
x = 2√6
The answer is one, because 1 is a absolute value so 1 x 10 is 10
Hi there!
First, let's create an equation for the table: m = 2n + 40. Using this equation, we can find the values of x, y, and z.
WORK:
x = 2(4) + 40
x = 8 + 40
x = 48
y = 2(5) + 40
y = 10 + 40
y = 50
z = 2(6) + 40
z = 12 + 40
z = 52
Next, using the equation, we know that the initial investment would be 40, since that is the y-intercept of the equation. To express M in terms of N, that would be our equation m = 2n + 40. To find 10 years, we'll plug in 10 for n.
WORK:
m = 2(10) + 40
m = 20 + 40
m = 60 after 10 years
To figure out when his investment would double, we'll need to use 80 (double his initial investment of 40) in place of m.
WORK:
80 = 2n + 40
40 = 2n
n = 20 years
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
