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Paladinen [302]
2 years ago
8

Can you show the steps thanks .........

Mathematics
1 answer:
Andrews [41]2 years ago
4 0

Answer:

40 black bears

Step-by-step explanation:

Hope it helps.

5 per sample

8 samples

5 x 8 = 40 black bears

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63% of 300 is what number ​
PolarNik [594]

Answer:

189

Step-by-step explanation:

You take 63% make it a decimal by dividing it by 100 and then you multiply it with 300. 300*.63=189.

6 0
3 years ago
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2/3 + (-5/7)<br><br><br><br> .........
dmitriy555 [2]

Answer:

-1/21

Step-by-step explanation:

2/3 + -5/7

Get a common denominator of 21

2/3 *7/7 = 14/21

-5/7*3/3 = -15/21

14/21 - 15/21 = -1/21

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3 years ago
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Enter the missing value into the box to complete the ratio comparing 75 centimeters to 3 meters. 1 to
Alex_Xolod [135]
The ratio for the problem above is one to four. A ratio is a relationship between number which describes how many times the second number contains the first number. The problem above gave two metric unit of length which are the centimeter and meter and the ratio between those two is one to a hundred. Therefore, we have a comparison between two amounts which are 75 and 300 and we can conclude a ratio of one to four.
5 0
2 years ago
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a player gets to throw 4 darts at the target shown. Assuming the player will always hit the target, the probability of hitting a
padilas [110]

Answer:

3.375

Step-by-step explanation:

(3/5)^3 / (2/5)^3 = 3.375

3 0
3 years ago
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solve this system of linear equations. separate the x- and y- values with a comma. 6x +5y=-19 12x-8y=52
Ymorist [56]

ANSWER

The solution is

(x,y)=(1,-5)

EXPLANATION

The equations are:

1st equation: 6x +5y=-19

2nd equation: 12x-8y=52

Multiply the first equation by 2:

3rd equation: 12x +10y=-38

Subtracy the 2nd equation from the 3rd equations.

12x-12x+10y--8y=-38-52

18y=-90

Divide both sides by 18.

y=-5

Put y=-5 into any of the equations and solve for x.

Preferably, the first equation will do.

6x +5(-5)=-19

6x -25=-19

6x=25-19

6x=6

x=1

The solution is

(x,y)=(1,-5)

8 0
2 years ago
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