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blondinia [14]
3 years ago
15

Deonte invested 200000at his bank for 10 years if he earned 130000 what was the interest rate the bank gave him

Mathematics
1 answer:
Volgvan3 years ago
8 0

<u>Answer:</u>

The interest rate the bank gave Deonte is 6.5%.

<u>Solution:</u>

Given, Deonte invested 200000 at his bank for 10 years  

He earned 130000  

We have to find what was the interest rate the bank gave him.

Now we know that, simple interest =\frac{\text {amount} \times \text {rate} \times \text {time}}{100}

So, by substituting our values in above formula,

130000=\frac{200000 \times \text { rate } \times 10}{100}

Interest rate \times 20000 = 130000

Interest rate \times 2 = 13

\text { Interest rate }=\frac{13}{2}=6.5 \%

Hence, the interest rate given by bank is 6.5% to Deonte.

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By the factor theorem, if x + 3 is a factor of f(x) = -3x^3 + 6x^2 + 6x + 9, then f(-3) = 0
f(-3) = -3(-3)^3 + 6(-3)^2 + 6(-3) + 9 = -3(-27) + 6(9) - 18 + 9 = 81 + 54 - 9 = 126.

Therefore, x + 3 is not a factor of the given function
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What is the solution to the equation Negative 3 (h + 5) + 2 = 4 (h + 6) minus 9?
ANTONII [103]

Answer:

h=-4

Step-by-step explanation:

Use the Distributive law:

1. -3(h+5) gives us -3h-15 then you add your two(2).

the whole of your left side of the equation will give you -3h-13

2. 4(h+6) gives us 4h+24 then you subtract nine(9).

the whole of the right side of the equation will give you 4h+15

3. equate the two like this:

-3h-13=4h+15

4. group like terms of each side:

-13-15=4h+3h

5. Add and Subt<u>r</u>act

-28=7h

6. Decide both sides by 7 to make h the subject of the formula

7. Congratulations you got your answer as h=-4

5 0
2 years ago
Please help, I need input on if I did this correctly and you just substitute.
kow [346]

The value of h(t) when t=\frac{15}{32} is 10.02.

Solution:

Given function h(t)=-16t^2+15t+6.5

To find the value of h(t) when t=\frac{15}{32}:

h(t)=-16t^2+15t+6.5

Substitute t=\frac{15}{32} in the given function.

$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5

            $=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5

Now multiply the common terms into inside the bracket.

           $=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

          $=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

        $=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}

        $=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}

        $=\frac{-225+450+416}{64}

       $=\frac{641}{64}

       = 10.02

$h\left(\frac{15}{32} \right)=10.02

Hence the value of h(t) when t=\frac{15}{32} is 10.02.

8 0
3 years ago
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