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Answer:
The width of Jim's garden is <u>5 feet</u>.
Step-by-step explanation:
Given:
Jim knows the length of his garden is 12 feet.
He knows the area of the garden is 60ft².
Now, to find the width of Jim's garden.
<em>Length = 12 feet.</em>
<em>Area = 60 ft²</em>.
Now, putting formula to get the width:


Dividing both sides by 12 we get:


Therefore, the width of Jim's garden is 5 feet.
Answer:
169.65
Step-by-step explanation:
N/7 = 54/42
we can multiply with 7 in both sides
(n/7)*7 = (54/42)*7
n = 9
Proof.
For two dice, the number of favorable cases is 5: (6, 2);(5, 3);(4, 4);(3, 5);(2, 6); so the
probability is 5/36 =
30/216
For three dice, the number of favorable cases is 21: (5, 2, 1), (4, 3, 1) counted with all permutations
(so 6 2 = 12), and (1, 1, 6), (2, 2, 4), (3, 3, 2), counted with the distinct permutations (so
3 3 = 9). The probability is 21/216
So the more likely case is for two dice.