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3 years ago

Name the x-axis of symmetry for the parabola down below

Mathematics

1 answer:

Artist 52 [7]3 years ago

7 0

Answer:

x = - 3

Step-by-step explanation:

The axis of symmetry is a vertical line passing through the vertex of the parabola with equation

x = c

where c is the value of the x- coordinates the line passes through

The line passes through (- 3, - 6), (- 3, 4 ) with x- coordinates - 3

Then equation of axis of symmetry is x = - 3

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The following figure shows A ABC with side lengths to the nearest tenth.

xz_007 [3.2K]

Answer:

17.7

Step-by-step explanation:

angle B = 180 - 81 - 65 = 34 degrees

as the sum of all angles in any triangle is always 180 degrees.

a/sin(A) = b/sin(B) = c/sin(C)

the sides are always on the opposite side of the angle.

so,

10/sin(34) = AB/sin(81)

AB = 10×sin(81) / sin(34) = 17.7

3 0

3 years ago

I spent 3/4 of my money and then I spent 1/5 of what was left.

Alborosie

1/20 is the fraction that you'll have left

6 0

3 years ago

1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,

crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

$PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}$

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

$PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111$

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

$PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666$

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

$PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222$

3 0

3 years ago

Is 3,611,756 divisible by 9? YES or NO HELP ME PLZ! T^T

Komok [63]

Answer:

NO IT IS NOT

Step-by-step explanation:

LOOK IN THE CALUCULATOR

6 0

2 years ago

Read 2 more answers

How many ways are there for six dogs and four cats to sit in a row in a strawberry field so that no two cats sit next to each ot

pickupchik [31]

Answer: 5,760

Step-by-step explanation:

$\\$ It was given that each dog is distinct from other dogs and each cat is distinct from other cats, Also from the hint given, the First position is for the dogs. $\\$ Let D represent the dogs and C represent the Cat , then we have

$\\$ D C D C D C D C D D or

$\\$ D D C D C D C D C D or

$\\$ D C DD C D C D C D or

$\\$ D C D C D D C D C D or

$\\$ D C D C D C DD C D

$\\$ Each of the arrangements above could be done in

$\\$ 2 x 4! x 4! ( it is constant that D is starting , so I am only left with the arrangement of the remaining 5 D's , out of the remaining 5 D's it is also constant that tow of them will be together and this could be done in 2 ways, so I have 4! left for the D's and 4! also for the C's )

$\\$ = 2 x 24 x 24

$\\$ = 1 , 152

$\\$ The total arrangement = 5 x 1 , 152

$\\$ = 5,7 60 ways

3 0

3 years ago