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Anettt [7]
3 years ago
15

Khan Academy Order Rational Numbers Please help, I will mark brainliest.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

C= -1/5

B= -0.4

C= -3/7

Step-by-step explanation:

You might be interested in
What is the square root of -1?
lora16 [44]

Answer:

i

Step-by-step explanation:

i means imaginary because whatever you try you can't get a number which squared gets a negative number.

4 0
3 years ago
Miranda earned $c for working 8 hours. Write an expression to show how much Miranda earned for each hour she worked.
BabaBlast [244]
$c/8 
You would substitute the c for the pay per hours and follow the expression through to determine each hour's pay, but since it's not asking for an equation, you don't need to add =(amount) to the end
3 0
3 years ago
Please help I’ll make brainliest
blondinia [14]

Answer:

Whats the directions?

Step-by-step explanation:

7 0
3 years ago
You were planning to spend $12 on a
nordsb [41]
You have $12, and need at least x more dollars to spend $30 total. So the inequality is 12 + x ≥ 30, where x is the number of dollars needed to get free delivery. To solve for x, subtract 12 from each side of the sign. x ≥ 30 - 12, x ≥ 18. You must spend at least 18 more dollars to qualify for free delivery.
8 0
2 years ago
(a) A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure
Temka [501]

Answer:

For first lamp ; The resultant probability is 0.703

For both lamps; The resultant probability is 0.3614

Step-by-step explanation:

Let X be the lifetime hours of two bulbs

X∼exp(1/1400)

f(x)=1/1400e−1/1400x

P(X<x)=1−e−1/1400x

X∼exp⁡(1/1400)

f(x)=1/1400 e−1/1400x

P(X<x)=1−e−1/1400x

The probability that both of the lamp bulbs fail within 1700 hours is calculated below,

P(X≤1700)=1−e−1/1400×1700

=1−e−1.21=0.703

The resultant probability is 0.703

Let Y be a lifetime of another lamp two bulbs

Then the Z = X + Y will follow gamma distribution that is,

X+Y=Z∼gamma(2,1/1400)

2λZ∼

X+Y=Z∼gamma(2,1/1400)

2λZ∼χ2α2

The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,

P(Z≤1700)=P(1/700Z≤1.67)=

P(χ24≤1.67)=0.3614

The resultant probability is 0.3614

8 0
3 years ago
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