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2 years ago

Can someone help

Mathematics

1 answer:

lubasha [3.4K]2 years ago

8 0

9514 1404 393

Answer:

C. jump discontinuity at x=-2

Step-by-step explanation:

At x=-2, you have to lift your pencil to keep drawing the graph. That means there's a jump discontinuity there.

This function has a jump discontinuity at x = -2.

<em>Additional comments</em>

At x=3, there is no discontinuity in the function. The <em>derivative</em> of the function has a discontinuity there, as there is an abrupt change in slope at that point.

If left and right limits exist and are the same at a point, but the graph is not defined at that point, then a <em>removable</em> discontinuity exists. All that is needed to fill the hole is to define the function at that point.

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what is the distance between the points (4, 5) and (10, 13) on a coordinte plane a. 12 units b. 8 units c. 10 units d. 14 units

qaws [65]

Answer:

<h2>10 units</h2>

Option C is the correct option

Step-by-step explanation:

Let the points be A and B

A ( 4 , 5 ) ------> ( x1 , y1 )

B ( 10 , 13 ) ------> ( x2 , y2 )

Now, let's find the distance between these points:

$\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

plug the values

$= \: \sqrt{(10 - 4) ^{2} + {(13 - 5)}^{2} }$

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$= \sqrt{ {(6)}^{2} + {(8)}^{2} }$

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Hope this helps..

Best regards!!

7 0

2 years ago

Solve for " x " <br><br><img src="https://tex.z-dn.net/?f=x%20%3D%20%2042%20-%209" id="TexFormula1" title="x = 42 - 9" alt="x =

disa [49]

$\implies {\blue {\boxed {\boxed {\purple {\sf {x\:=\:33}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$x = 42 - 9$

➼ $\:x = 33$

Therefore, the value of $x$ is 33.

$\sf\pink{Thank\:you. \:ヅ}$

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coldgirl [10]

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