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Black_prince [1.1K]
3 years ago
14

Write the numbers in order from least to greatest.3.4 2.9 √15 √6

Mathematics
2 answers:
Liula [17]3 years ago
7 0

Answer:

2.9, √6, 3.4, √15

Step-by-step explanation:

2.9 is smaller than √6 because √6 simplified is 3.

[3.4] = 3 as integers less than 3.4 are 3, 2, 1, ... square root of all these numbers will be greater than equal to 1 but less than 2. ... From [√9 ] to [ √15], the value of each term is 3 and total of these 7 terms is 21.

nikdorinn [45]3 years ago
3 0

Answer:

√6, 2.9, 3.4, √15

Step-by-step explanation:

the square root of 6 = 2.4

the square root of 15 would be 3.9 (3.87)

2.4 < 2.9 < 3.4 < 3.9

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8 0
3 years ago
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A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years
juin [17]

Answer: 0.55567

Step-by-step explanation:

Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.

i.e.

\mu=10\text{ years}\\\sigma=3\text{ years}

Let X_1 and X_2 are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator X_3 .

So that, X =X_1+X_2-1.9\times X_3

Mean =E(X_1)+E(X_2)-E(X_3)=10+10-1.9\times10 =1

Standard deviation =\sqrt{(Var(X_1)+Var(X_1)+Var(X_1))}

=\sqrt{(3^2+3^2+(1.9\times3)^2)}

=7.1056315694

Z-score : z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14

Now , The  probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-

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3 years ago
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4 0
2 years ago
6×11÷2what do you think it could be
Valentin [98]
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7 0
3 years ago
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Answer:

(g\circ h)(x)=-x^2-x-3

Step-by-step explanation:

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(g\circ h)(x)

This is the same thing as:

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So, substitute h(x) into g(x):

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Distribute the negative:

g(h(x))=-x^2-x-3

And we're done!

So:

(g\circ h)(x)=-x^2-x-3

6 0
2 years ago
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