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Archy [21]
3 years ago
9

Prove that 25^11 - 5^19 is divisible by 31.

Mathematics
1 answer:
Stells [14]3 years ago
7 0

Answer:

See below  

Step-by-step explanation:

                                        25¹¹ - 5¹⁹

Convert to base 5       = (5²)¹¹ - 5¹⁹

                                    =  5²²   - 5¹⁹

Factor out the GCF     =  5¹⁹(5³ - 1)

                                    =  5¹⁹(125 - 1)

                                    =  5¹⁹ × 124

                                    =  5¹⁹ × 4 × 31

31 is a factor of 25¹¹ - 5¹⁹, so the expression is divisible by 31.

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Answer:

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Step-by-step explanation:

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What is the value of 54-4a^2+3b^3 when a=-2 and b=4
max2010maxim [7]

2015-12-14T20:17:50+00:00If you would like to know what is the value of <span>54 - 4 * a^2 + 3 * b^3 </span>when a = -2 and b = 4, you can calculate this using the following steps:

54 - 4 * a^2 + 3 * b^3 = 54 - 4 * (-2)^2 + 3 * 4^3 = 54 - 4 * 4 + 3 * 64 = 54 - 16 + 192 = 230

If you would like to know what is the value of 54 - 4 * a^2 - 3 * b^3 when a = -2 and b = 4, you can calculate this using the following steps:

54 - 4 * a^2 - 3 * b^3 = <span>54 - 4 * (-2)^2 - 3 * 4^3 = 54 - 4 * 4 - 3 * 64 = 54 - 16 - 192 = -154</span>
8 0
3 years ago
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Please solve the question
Margarita [4]

U should do like this... But sry I don't know third part

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3 years ago
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Answer:

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3 years ago
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