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4 years ago

What is the rule for subtractions fractions?

Mathematics

2 answers:

Verdich [7]4 years ago

8 0

Answer:

You must make the dominators (the bottom numbers) equal to each other.

Illusion [34]4 years ago

8 0

The one above is correct :)

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Find lim h→0 f(2+h)-f(2)/h if f(x)=x^2+x+1

bekas [8.4K]

Answer:

Step-by-step explanation:

$\displaystyle \lim_{h \to 0} \frac{f(2+h)-f(2)}{h}$

$\displaystyle\lim_{h \to 0} \frac{(2+h)^2 + 2 + h + 1 - 2^2 - 2 - 1}{h}$

$\displaystyle\lim_{h \to 0} \frac{4 + 4h + h^2 + h - 4}{h}$

$\displaystyle\lim_{h \to 0} \frac{h^2 + 5h}{h}$

$\displaystyle\lim_{h \to 0} h + 5$

= 5

8 0

3 years ago

Please help me I need help please

MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

$x^2+(p-3)y^2-4x+6y-16=0$

Standard equation of a circle:

$(x-a)^2+(y-b)^2=r^2$

(where $(a,b)$ is the centre of the circle, and $r$ is the radius)

If you expand this equation, you will see that the coefficient of $y^2$ is always one.

Therefore, $p-3=1$

$\implies p=1+3=4$

Additional information

To rewrite the given equation in the standard form:

$\implies x^2+y^2-4x+6y-16=0$

$\implies x^2-4x+y^2+6y=16$

$\implies (x-2)^2-4+(y+3)^2-9=16$

$\implies (x-2)^2+(y+3)^2=16+4+9$

$\implies (x-2)^2+(y+3)^2=29$

So this is a circle with centre (2, -3) and radius √29

3 0

2 years ago

45 + 57 = x + y x= 37 y =?

Mekhanik [1.2K]

Answer:

y = 65

Step-by-step explanation:

45 + 57 = x + y

x = 37

45 + 57 = 37 + y

45 + 57 = 102

102 = 37 + y

-37 -37

102 - 37 = 65

37 + y - 37 = y

65 = y

y = 65

5 0

3 years ago

Read 2 more answers

What is 4/9 • t when t=1/3

Reptile [31]

$\frac{4}{9}* \frac{1}{3}= \frac{4}{27}$

8 0

4 years ago

Read 2 more answers

PLEASE HELP! Which statement is true?

Gekata [30.6K]

2nd one is correct answer

7 0

3 years ago