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ArbitrLikvidat [17]
3 years ago
15

A coin which is tossed straight up into the air. After it is released it moves upward, reaches its highest point and falls back

down again. Use one of the following choices (A through G) to indicate the force acting on the coin for each of the cases described below. Answer choice J if you think that none is correct. Ignore any effects of air resistance.
(A) The force is down and constant
(B) The force is down and increasing
(C) The force is down and decreasing
(D) The force is zero.
(E) The force is up and constant.
(F) The force is up and increasing
(G) The force is up and decreasing
Mathematics
1 answer:
Helen [10]3 years ago
4 0

Answer:

Answers  G, and A

Step-by-step explanation:

the motion of a body is as a result of the various forces acting on it.

As the coin is tossed upwards an upwards force acts on it and this force decreases up to the highest point the coin reaches. at the highest point the force of gravity applies. This force is downwards and constant (9.8m/s^{2}).

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\bold{\huge{\underline{ Solution }}}

<u>Before </u><u>answering </u><u>the </u><u>given </u><u>question</u><u>, </u><u>you </u><u>should </u><u>know </u><u>the </u><u>difference </u><u>between </u><u>polygon </u><u>and </u><u>regular </u><u>polygon</u><u>. </u>

  • Polygon :- It is closed figure constitute of straight line having different measurements and also having varies angles.
  • Regular polygon :- It is also a closed figure constitute of straight lines which having equal measuresment and all the angles of the given polygon are equal .

<u>There </u><u>are </u><u>different </u><u>types </u><u>of </u><u>polygon </u><u>based </u><u>on </u><u>the </u><u>sides </u><u>:</u><u>-</u>

  • A polygon having 3 sided called triangle ,having 4 sides called quadrilateral ,having 5 sides pentagon and so on.

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u></h3>

I have thought to make a 4 side polygon that is quadrilateral.

<u>Steps </u><u>of </u><u>construction </u><u>:</u><u>-</u><u> </u>

  • Step - 1 :- Draw a 5 cm line AB horizontally
  • Step - 2 :- Then , From a point B, Draw a Vertical line of 5 cm and named it BC
  • Step - 3 :- Then, From a point C, Draw a horizontal line of 5 cm and named it CD
  • Step - 4 :- Now, join the line AD
  • Step - 5 :- Measure all the angles form by the 4 sides of the quadrilateral.

<u>Result </u><u>:</u><u>-</u><u> </u> All the angles are equal that is 90° each.

<u>Conclusion </u><u>:</u><u>-</u><u> </u> The above figure is square as it is having equal sides and angles.

<h3><u>Now</u><u>, </u><u>we </u><u>have </u><u>to </u><u>find </u><u>the </u><u>sum </u><u>of </u><u>the</u><u> </u><u>angles</u><u> </u><u>of </u><u>the </u><u>polygon </u><u>:</u><u>-</u></h3>

<u>Here</u><u>, </u><u> </u>

  • All angles are equal in measure 90°

<u>Therefore</u><u>, </u>

The sum of the angles of the given polygon

\sf{ = 90{\degree} + 90{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 180{\degree} + 90{\degree} + 90{\degree} }

\sf{ = 270{\degree} + 90{\degree} }

\sf{ = 360{\degree} }

Hence, The sum of the angles of the above polygon is 360° .

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