The answer to your problem would be 10.
if two figures are congruent, each side is congruent to the same side on the other figure.
AB=FG; CD=HI; EA=JF
since CD=HI, and CD=10, then HI would also equal 10
F(x) = x^2 - 6x + 4 {-3, 0, 5} (x, y) x is the domain, y is the range.
plug in the domain numbers into the equation to find the range.
y = x^2 - 6x + 4
y = -3^2 - 6(-3) + 4
y = 9 - (-18) + 4
y = 9 + 18 + 4
y = 31 (-3, 31)
y = x^2 - 6x + 4
y = 0^2 - 6(0) + 4
y = 0 - 0 + 4
y = 4 (0, 4)
y = x^2 - 6x + 4
y = 5^2 - 6(5) + 4
y = 25 - 30 + 4
y = -1 (5, -1)
c. {-1, 4, 31}
hope this helped, God bless!
Both are equal y. So you can set them equal to each other
9x+13=2x+48
Subtract 2x from both sides
7x+13=48
Subtract 13 from both sides
7x= 35
X=5
Answer: 32/56, 0.57, 57% rounded = 60%
Step-by-step explanation: 8 times 7 =56 and 8 times 4= 32. our fraction is 32/56. divide 32 by 56 to make out a decimal= 0.57. Multiply 0.57 by 100 to make out a percent = 57%
False
A arithmetic sequence is a sequence that has a difference of 2. We see that we have -17 ... and then we have 2 ... and then 21. There is NOT a difference of 2, as we can see. Therefore, yiur answer would be (false).
