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gayaneshka [121]
2 years ago
12

Which is the graph of x Greater-than-or-equal-to 98.6? A number line going from 95 to 103. A closed circle is at 98.6. Everythin

g to the right of the circle is shaded. A number line going from 95 to 103. An open circle is at 98.6. Everything to the right of the circle is shaded. A number line going from 95 to 103. An open circle is at 98.6. Everything to the left of the circle is shaded. A number line going from 95 to 103. A closed circle is at 98.6. Everything to the left of the circle is shaded.
Mathematics
2 answers:
DENIUS [597]2 years ago
3 0

Answer:

A number line going from 95 to 103. A closed circle is at 98.6. Everything to the right of the circle is shaded.

Step-by-step explanation:

We want to determine the graph of x\geq 98.6.

Since we have the sign, \geq, we use a closed circle to show that the number 98.6 is included in the domain of definition.

Then since the sign is greater than, we shade to the right of 98.6.

The correct option is A.

scZoUnD [109]2 years ago
3 0

I will say it fast the answer is A

Step-by-step explanation:

And hi

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\boxed{1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}=5}

<h2>Explanation:</h2>

in this problem we have the following expression:

1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}

So here:

1 \frac{1}{2} \ and \ 1 \frac{1}{9} \ are \ written \ as \ mixed \ fractions

Let's convert them as improper fractions:

1 \frac{1}{2}=1+\frac{1}{2}=\frac{1\times 2+1}{2}=\frac{3}{2} \\ \\ 1 \frac{1}{9}=1+\frac{1}{9}=\frac{1\times9 +1}{9}=\frac{10}{9}

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\frac{3}{2}\times 3 \times \frac{10}{9}=\frac{3\times 3 \times 10}{2\times 9}=\frac{90}{18}=5

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

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Answer:

a) P(x<5)=0.

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f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \,  otherwise }} \right.

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P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

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d)  We calculate the probability that you will be late to each of the 9:30am classes next week:

P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

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