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Stels [109]
3 years ago
15

A bag contains 3 red marbles and 4 blue marbles.A marble is taken out from the bag and replaced. Another marble is taken from th

e bag. Work out the probability that the two marbles taken from the bag are the same colour.
Mathematics
2 answers:
My name is Ann [436]3 years ago
5 0
A bag contains 3 red marbles and 4 blue marbles. a marble is taken at random and replaced. Another marble is taken from the bag. Work out the probability that the two marbles taken from the bag are the same color.

<span>Total number of marbles in the bag is 3 + 4 = 7.<span>The problem asks for the probability of (RR) or (BB).</span>It's worthy to note we are replacing the balls after each draw, which means we always have 7 to draw from</span>Since each draw is independent, we take the product of each event for the total event probability.

P(RR) = 3/7 * 3/7 = 9/49
P(BB) = 4/7 * 4/7 = 16/49

We want to know P(RR) + P(BB)
<span>P(RR) + P(BB) = 9/49 + 16/49 = 25/49</span>
allsm [11]3 years ago
4 0
I think 2/7 would be the probability 
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28.5

Step-by-step explanation:

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Solve the system by substitution<br><br> -5x+3y=2<br> y=2x
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Answer:

(x,y)=(0,0)

Step-by-step explanation:

Simplify -5x+3y=2x

2y=2x

multiply both sides -7x+3y=0

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2 years ago
A study dealing with health care issues plans to take a sample survey of 1500 Americans to estimate the mean dollar amount that
frutty [35]

Answer:

The population parameter of this study is the population mean.

Step-by-step explanation:

A population parameter is a numerical measure representing a certain characteristic of the population. For example, population mean, population variance, population proportion, and so on.

The population parameter is computed using all the values of the population.

The population parameter can be estimated using the sample statistic. If the value of the population parameter is not known, then a random sample of large size, say <em>n</em> ≥ 30 can be selected from the population and the statistic value can be computed. This statistic value is considered as the point estimate of the parameter. It is also known as the unbiased estimator of the parameter.

In this case the survey involved sampling of 1500 Americans to estimate the mean dollar amount that Americans spent on health care in the past year.

The sample selected is used to compute the sample mean dollar amount that Americans spent on health care.

So, the population parameter of this study is the population mean.

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2 years ago
Petes dog weighed 30 pounds it then lost 16% of it's weight how much did pete lose
Vlad [161]

Answer:

The dog lost 4.8 pounds! Goodluck!


Step-by-step explanation:


6 0
2 years ago
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The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
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