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2 years ago

A student was asked to calculate the missing leg of

Mathematics

1 answer:

Bezzdna [24]2 years ago

8 0

Lambodar hai toh yeh student Student was asked to calculate the missing leg of the

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The ratio of Aziz's money to Osman's money was 2:1 at first. After Aziz spent $10 ratio became 4:3. How much money did each boy

Dvinal [7]

Answer:

Aziz's money was $30

Osman's money was $15

Step-by-step explanation:

Let

x-----> Aziz's money at first

y-----> Osman's money

we know that

$\frac{x}{y}=\frac{2}{1}$

$x=2y$ ------> equation A

$\frac{x-10}{y}=\frac{4}{3}$ -----> equation B

substitute equation A in equation B and solve for y

$\frac{2y-10}{y}=\frac{4}{3}\\ \\6y-30=4y\\ \\6y-4y=30\\ \\2y=30\\ \\ y=15$

Find the value of x

$x=2(15)=30$

therefore

At first

Aziz's money was $30

Osman's money was $15

8 0

2 years ago

^ { (5x ^ { 3 } -7x ^ { 2 } +3x-4)-(8x ^ { 3 } +2x ^ { 2 } +3x-7) }

Tomtit [17]

Answer:

$-3x^{3} -9x^2+3$

Step-by-step explanation:

Given

$(5x^{3} -7x^{2} +3x-4)-(8x ^ { 3 } +2x ^ { 2 } +3x-7) }$

Required

Simplify

$(5x^{3} -7x^{2} +3x-4)-(8x ^ { 3 } +2x ^ { 2 } +3x-7) }$

Open brackets

$5x^{3} -7x^{2} +3x-4-8x^3 -2x^2 -3x+7$

Collect Like Terms

$-8x^3+5x^{3} -7x^{2} -2x^2+3x -3x-4+7$

Simplify like terms

$-3x^{3} -9x^2+3$

6 0

2 years ago

What is log b^b^6x equivalent to (The b is under log and ^b)? How do you know?

Arturiano [62]

Answer: 6x

Work Shown:

For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that $\log_b(b) = 1$ meaning that the log base of itself is 1