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3 years ago

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Still need help on this please need help

1 answer:

Goryan [66]3 years ago

6 0

The discriminant is the value of b²-4ac
in this case, b=-8, a=4, c=4, so the discriminant is (-8)²-4*4*4=0
when the discriminant is 0, there is one rational solution.
when the discriminant is larger than 0, there are two rational solutions.
when the discriminant is smaller than 0, there are no real solutions. <span />

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How many solutions are there to the equation below?<br> 6x + 33 = 6(x+6)

Ainat [17]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's solve ~

$6x + 33 = 6(x + 6)$

$6x + 33 = 6x + 36$

Here, 6x is present on both the sides of equation so they cancel out ~ therefore there is no one solution satisfying the equation ~

3 0

2 years ago

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Me ajuda ai por favor tenho que entregar amanhã

elena-14-01-66 [18.8K]

a) (2a - b)² = (4a² - 4ab + b²)

b) (10m - n²)² = (100m² - 20mn² + n⁴)

c) (4x - 4²) = (16x² - 8x + 4⁴)

d) ${( \frac{1}{3} x - y) }^{2} = ({ \frac{1}{9}x }^{2} - \frac{2}{3} xy + {y}^{2} )$

e)

$(0.25 - a) ^{2} = (0.25^{2} - (2)(0.25)a + {a}^{2} ) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = ( \frac{1}{16} - \frac{1}{2} a + {a}^{2} )$

f)

${( \frac{2x}{3} - \frac{1}{2} )}^{2} = ( \frac{4 {x}^{2} }{9} - \frac{2x}{3} + \frac{1}{4} )$

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2 years ago

Complete the coordinate proof of the theorem. Given: A B C D is a rectangle. Prove: The diagonals of A B C D are congruent.

Inessa05 [86]

Step-by-step explanation:

<u>Given coordinates of the rectangle ABCD:</u>

A(0, 0), B(a, 0), C(x, y), D(0, b)

Lets first find coordinates of C

We can see that A and B are on same line horizontally, so C and D will be on the parallel line

The distance AB and CD are equal also distance AD and BC are equal, therefore

AB = a - 0 = a, CD = a
AD = b - 0 = b, BC = b

<u>So the coordinates of C are:</u>

x = a, y = b

<u>Now the diagonals:</u>

AC = √(a-0)² + (b-0)² = √a²+b²
BD =√(0-a)² + (b -0)² = √a² + b²

Since AC = BD, we can state they are congruent

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2 years ago

Read 2 more answers

In the figure below, Z is the center of the circle. Suppose that OR=4, ST= 4, UZ= 6, and VZ=4x-6. Find the following.

Ann [662]

Answer:

x = 3 units

SV = 2 units

Step-by-step explanation:

In $\odot Z$ QR and ST are chords such that:

QR = ST = 4

That is both the chords are equal in measure.

Equal chords are at equal distance from the center of the circle. Therefore,

VZ = UZ

4x - 6 = 6

4x = 6 + 6

4x = 12

x = 12/4

x = 3 units

Since, perpendicular dropped from the center of the circle bisects the chord.

$\therefore SV = \frac{1}{2} ST$

$\therefore SV = \frac{1}{2} \times 4$

$\therefore SV = 2\: units$

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2 years ago

A dog is leashed to the corner of a house. How much running area does the dog have? Round answer to the nearest square foot, if

sashaice [31]

Answer:

942 ft²

Step-by-step explanation:

The diagram shows the area to be 3/4 of that of a circle of radius 20 ft. The area of a circle is given by ...

A = πr² = π(20 ft)² = 400π ft²

Then 3/4 of that area is ...

dog run = (3/4)(400π ft²) = 300π ft² ≈ 942.48 ft²

The area of the dog's run is about 942 ft².

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3 years ago