
Let's solve ~
Here, 6x is present on both the sides of equation so they cancel out ~ therefore there is no one solution satisfying the equation ~
a) (2a - b)² = (4a² - 4ab + b²)
b) (10m - n²)² = (100m² - 20mn² + n⁴)
c) (4x - 4²) = (16x² - 8x + 4⁴)
d)
e)

f)

Step-by-step explanation:
<u>Given coordinates of the rectangle ABCD:</u>
- A(0, 0), B(a, 0), C(x, y), D(0, b)
Lets first find coordinates of C
We can see that A and B are on same line horizontally, so C and D will be on the parallel line
The distance AB and CD are equal also distance AD and BC are equal, therefore
- AB = a - 0 = a, CD = a
- AD = b - 0 = b, BC = b
<u>So the coordinates of C are:</u>
<u>Now the diagonals:</u>
- AC = √(a-0)² + (b-0)² = √a²+b²
- BD =√(0-a)² + (b -0)² = √a² + b²
Since AC = BD, we can state they are congruent
Answer:
x = 3 units
SV = 2 units
Step-by-step explanation:
In
QR and ST are chords such that:
QR = ST = 4
That is both the chords are equal in measure.
Equal chords are at equal distance from the center of the circle. Therefore,
VZ = UZ
4x - 6 = 6
4x = 6 + 6
4x = 12
x = 12/4
x = 3 units
Since, perpendicular dropped from the center of the circle bisects the chord.

Answer:
942 ft²
Step-by-step explanation:
The diagram shows the area to be 3/4 of that of a circle of radius 20 ft. The area of a circle is given by ...
A = πr² = π(20 ft)² = 400π ft²
Then 3/4 of that area is ...
dog run = (3/4)(400π ft²) = 300π ft² ≈ 942.48 ft²
The area of the dog's run is about 942 ft².