The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)
----------------(from equation 1)
----------------(given p=58 inches)
----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.
as, -----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Im not 100% sure but
A: 10
B: 5
C: 15
D: 30
for:
A: 30 x 1/3
B: 15 x 1/3
C: 5/ 1/3
D: 10/ 1/3
Answer:
64^(4/6) = 16
Step-by-step explanation:
Answer:
10.2 ft
Step-by-step explanation:
64 + = 169
b=
b= 10.2469