The formula for the radius r in terms of x . and for the maximum areas is x=2/
+4
Given that,
y forms a circle of radius r
y=2
r
r=y/2
(2-y)- forms Square Side x
(2-y) = 4x
x=(2-y)/4
Now Sum of Area's=Area of Square +Area of Circle
Sum =
r² + x²
Substitute the r and x values in above equation,
A(y)= y²/4
+(y-2)²/ 16
To maximize Area A(y)
A'(y)= 0
2y/4
+ 2(y-2)/16 =0
y/2
+ (y-2)/8 =0
y = 2
/
+4
Y max will be max, x to be maximum.
for maximum sum of areas,
x=2/
+4
Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/
+4
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This is how the first one would be done. sorry if it’s a little messy the answer is 9. but try using photomath for the rest. it gives you the answer and explains how to do it
6a³-18a²-1620a
Collect 6a:
6a(a²-3a-270)
6a(a-18)(a+15)