Answer:
C. The specific field of study
C. change in anesthetic agent
Explanation:
In the consideration for the procedure, some information are required and examples are the strategy of the search/the database name. However, the area of study is not one of the information.
The animal use proposal can general be altered based on the type of change required. However, an anesthetic agent alteration is not a significant change.
Answer:
Key escrow.
Explanation:
If a full disk encryption (FDE) password is forgotten, a key escrow can be incorporated to securely store the encryption key to unlock the disk.
A key escrow can be defined as a data security method of storing very essential cryptographic keys.
Simply stated, key escrow involves a user entrusting his or her cryptographic key to a third party for storage.
As a standard, each cryptographic key stored or kept in an escrow system are directly linked to the respective users and are encrypted in order to prevent breach, theft or unauthorized access.
Hence, the cryptographic keys kept in an escrow system are protected and would not be released to anyone other than the original user (owner).
<em>Therefore, when a full disk encryption (FDE) password is forgotten, a key escrow if incorporated can be used to retrieve the password. Subsequently, the password would then be used to unlock or decrypt the disk.</em>
Answer:
Hi there! Please find the answer below.
Explanation:
The program below demonstrates how each of the requirements can be coded in a simple Python script. To copy the array, we can use the copy() method of the array. To calculate the diff, we can use a few different techniques, so I have implemented it using a loop over the arrays and just storing and displaying the difference in the 2 arrays.
new_string.py
def add_test_score(score):
test_score.append(score);
contact_hash = {}
test_score = []
print("Enter 5 test scores: ");
for x in range(0, 5):
input_string = input("Enter test score " + str(x + 1) + ": ")
add_test_score(int(input_string));
print(test_score);
test_score_copy = test_score.copy();
for e in test_score_copy:
if e < 60:
test_score_copy[test_score_copy.index(e)] += 10;
diff = [];
for e in test_score:
print(test_score[test_score.index(e)]);
print(test_score_copy[test_score.index(e)]);
if not test_score[test_score.index(e)] == test_score_copy[test_score.index(e)]:
diff.append(e);
print(diff);
Answer:
D
Explanation:
All three of A, B and C are required to harden a host. Thus, All of the above makes the best option.
Hardening simply refers to making your data impossible to be penetrated. More like bulletproof.
To do this, ensure measures like
- Regular Program cleanup
- Patches management
- service pack installation
- service or usage policies
...among others.
Cheers
