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Illusion [34]
3 years ago
13

Write a method named lastFirst that accepts a string as its parameter representing a person's first and last name. The method sh

ould return the person's last name followed by the first initial and a period. For example, the call lastFirst("Marla Singer") should return "Singer, M." . You may assume that the string passed consists of exactly two words separated by a single space.
Computers and Technology
1 answer:
Usimov [2.4K]3 years ago
7 0

I'm going to assume this is Java, because you said "method" meaning it will be some sort of object oriented language, and Java's really common. Here would be the full program, but you can just take the method out isolated if you need it.

package lastname;

public class LastName {

   public static void main(String[] args) {

       // Example usage:

       String name = LastName.lastName("Garrett Acord");

       System.out.println(name);

       // Output: Acord G.

   }

   public static String lastName(String fullName)

   {

       String[] splitName = fullName.split(" ");

       return String.format("%s %s.", splitName[1], splitName[0].substring(0,1) );

       

   }

   

}

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to multiply 50 in cell D3 by 8.90 in cell E3 the formula to be used is

=D3*E3

This will multiply the numbers in both cell and show as 445.

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3 years ago
Add the following 2's complement binary numbers. Also express the answer in decimal. a. 01+ 1011b. 11+ 01010101c. 0101+ 110d. 01
kenny6666 [7]

Answer:

(a) 01 + 1011

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 1011

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1       ------------------> + 1 (in decimal)

<u>1  0 1  1 </u>      ------------------> - 5 (in decimal)

<u>1  1  0 0 </u>    -------------------> - 4 (in decimal)

Explanation for (a)

<em>01 or 0001</em>

Since the most significant bit is 0 (leftmost bit), it shows that it is a positive number. Therefore, it can be directly converted to its decimal representation as follows:

0001 = 0 x 2^{3} + 0 x 2^{2} + 0 x 2^{1} + 1 x 2^{0} = 1

0001 is + 1 in decimal.

<em>1011</em>

Its most significant bit(MSB) is 1 showing that it is negative.

Flipping all its bits and adding 1 to the result, will convert it to it's positive counterpart.

i.e 1011 => 0100 + 1 = 0101.

Converting the result (0101) to decimal gives

0101 = 0 x 2^{3} + 1 x 2^{2} + 0 x 2^{1} + 1 x 2^{0} = 5

1011 is -5 in decimal

<em>01 + 1011 or 0001+ 1011 = 1100</em>

The result (1100), of the addition of the two numbers, is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1100 => 0011 + 1 = 0100.

Converting the result (0100) to decimal gives

0100 = 0 x 2^{3} + 1 x 2^{2} + 0 x 2^{1} + 0 x 2^{0} = 4

Therefore, the result, 1100 is -4 in decimal.

===================================================

(b) 11 + 01010101

Convert the two numbers into their 8-bit representation since one of them is in 8-bit.

PS: Taking 11, its MSB is 1 showing that it is a negative number. Also, it's 8-bit representation will mean pre-padding it with ones(1s) rather than zeros as follows. In other words, pre-padding a 2's complement  number is done using its sign bit.

=> 11 = 11111111

=> 01010101

Addition of the two numbers (in their 2's complement form) gives the following:

  1  1  1  1  1  1  1  1       ------------------> - 1 (in decimal)

<u>   0 1  0 1  0  1 0 1 </u>      ------------------> + 85 (in decimal)

<u>1 0 1  0 1  0  1 0 0</u>    ------------------->  + 84 (in decimal)

Discard the carry-out bit (1) making the result 01010100

Explanation for (b)

<em>11 or 11111111</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

11111111 => 00000000 + 1 = 00000001

Converting the result (00000001) to decimal gives 1

11 or 11111111 is  - 1 in decimal.

<em>01010101</em>

Its MSB is 0 showing that it is also positive. Now, convert to decimal

01010101 = 85

01010101 is + 85 in decimal.

<em>11111111 + 01010101 = 01010100</em>

The result (01010100), is also positive as the MSB is 0. Now, convert to decimal.

01010100 = 84

Therefore the result (01010100) is + 84 in decimal.

===================================================

(c) 0101 + 110

Convert the two numbers into their 4-bit representations.

=> 0101 = 0101

=> 110 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

     0 1 0 1       ------------------> + 5 (in decimal)

<u>      1  1 1  0 </u>      -----------------> - 2 (in decimal)

<u>   1 0 0 1  1 </u>    -------------------> + 3 (in decimal)

Dicard the carry-out bit (leftmost bit) to get 0011 as result.

Explanation for (c)

<em>0101</em>

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now, convert to decimal.

0101 =  5

0101 is +5 in decimal.

<em>110 or 1110</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010 =  2

1110 is -2 in decimal

<em>0101 + 110 = 0101+ 1110 = 0011</em>

The result (0011), is a positive number as the MSB is 0.

Converting the result (0011) to decimal gives

0011 = 3

Therefore, the result, 0011 is 3 in decimal.

===================================================

(d) 01 + 10

Convert the two numbers into their 4-bit representation.

=> 01 = 0001

=> 10 = 1110

Addition of the two numbers (in their 2's complement form) gives the following:

0 0 0 1       ------------------> + 1 (in decimal)

<u>1  1  1  0 </u>      ------------------> - 2 (in decimal)

<u>1  1  1  1 </u>    -------------------> - 1 (in decimal)

Explanation for (d)

<em>01 or 0001</em>

Since the MSB is 0 (leftmost bit), it shows that it is a positive number. Now convert to decimal.

0001 = 1

0001 is + 1 in decimal.

<em>1110</em>

Its MSB is 1 showing that it is negative.

Convert it to it's positive counterpart.

i.e 1110 => 0001 + 1 = 0010.

Converting the result (0010) to decimal gives

0010  = 2

1110 is -2 in decimal

<em>01 + 1011 or 0001+ 1110 = 1111</em>

The result (1111), is a negative number as the MSB is 1.

Convert it to it's positive counterpart.

i.e 1111 => 0000 + 1 = 0001.

Converting the result (0001) to decimal gives

0001 = 1

Therefore, the result, 1111 is -1 in decimal.

7 0
4 years ago
Ada lovelace designed the first computer
muminat

Answer:      yes.                        

this was A very good question and after alot of digging up i finally found the answer by searching who was the first computer programmer on google :3

8 0
3 years ago
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