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MatroZZZ [7]
3 years ago
7

A Web music store offers two versions of a popular song. The size of the standard version is 2.1 megabytes (MB). The size of the

high-quality version is
4.8 MB. Yesterday, there were 1010 downloads of the song, for a total download size of 3039 MB. How many downloads of the high-quality version were there?
Mathematics
2 answers:
Jet001 [13]3 years ago
7 0
 i will say that there were 260 high-quality downloads!
Paraphin [41]3 years ago
4 0
Is there any A. B. C. or D.???
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(4^3)^7 <br><br> please answer quickly!!
faltersainse [42]

Answer:

4,398,046,510,000 or 4^21

Step-by-step explanation:

If you need to solve:

(4^3)^7

4^3= 64

64^7= 4.39804651×10^12 or 4,398,046,510,000

If you just need the exponents answer:

You multiply exponents so the answer would be 4^21

4 0
3 years ago
Yasmin bought several items at the discount store. She paid 8.75 percent sales tax, an amount of $4.59, on the total amount of h
sveticcg [70]

divide the total tax by the rate

8.75% = 0.0875

4.59/.0875 = 52.457 round to 52.46

6 0
3 years ago
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Evaluate a^7 - 4b for a =3 and b= -1
Papessa [141]

Answer:

2187+4

= 2191

Step-by-step explanation:

plz brainliest :)

3 0
3 years ago
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Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
2. What is the slope of the line pictured? X​
saul85 [17]

Answer:

y= -2x+2

Step-by-step explanation:

4 0
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