So she rode the Ferris Wheel 4 times. 8/2= 4
Since we removed one ace out of 52 cards now remains 51 cards and 3 aces.
The answer is 3/51
For this case, the first thing we must do is define variables.
We have then:
x: number of blue beads
y: number of red beads
We now write the inequations system:
Answer: a system of linear inequations that represents the situation is:
<h3>
Answer: b = 4 and c = 7.</h3>
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Explanation:
Comparing y = x^2+bx+c to y = ax^2+bx+c, we see that a = 1.
The vertex given is (-2,3). In general, the vertex is (h,k). So h = -2 and k = 3.
Plug those three values into the vertex form below
y = a(x-h)^2 + k
y = 1(x-(-2))^2 + 3
y = (x+2)^2 + 3
Then expand everything out and simplify
y = x^2+4x+4 + 3
y = x^2+4x+7
We see that b = 4 and c = 7.
I don’t think it is, sorry I’m not 100% sure, good luck though