It should be c really hope this helps and im right have a blessed day:)
<span>x in (-oo:+oo)
((5-9*x)^1)/2 = ((4*x+3)^1)/2 // - ((4*x+3)^1)/2
((5-9*x)^1)/2-(((4*x+3)^1)/2) = 0
(5-9*x)/2-((4*x+3)/2) = 0
(5-9*x)/2+(-1*(4*x+3))/2 = 0
5-1*(4*x+3)-9*x = 0
2-13*x = 0
(2-13*x)/2 = 0
(2-13*x)/2 = 0 // * 2
2-13*x = 0
2-13*x = 0 // - 2
-13*x = -2 // : -13
x = -2/(-13)
x = 2/13
x = 2/13</span>
Answer:
Step-by-step explanation:
This is an Annuity question. It is asking for recurring monthly payment(PMT). <em>You can use a financial calculator to solve it. I am using (Texas Instruments BA II plus)</em>
Since the payments occur monthly , adjust the interest rate to monthly rate and multiply 40 years by 12 since we have 12 months in a year<em>.</em>
Total duration of investment ; N = 40*12 = 480
Interest rate; I/Y = 5.75% /12 = 0.4792%
Future value; FV = 6,000,000
Present value ; PV = 0
then CPT PMT = 3,222.912
Therefore $3,222.91 should be deposited each month to achieve the goal.
Answer:
700
Step-by-step explanation:
25 x 28
there is only one property and its multiplication
Answer:
a
mean 
variance 
b
The binomial random variable x fall into this interval ranges from
- 5 to 5
c
Step-by-step explanation:
From the question we are told that
The sample size is 
The percentage that look for gas stations and food outlets that are close to or visible from the highway is 
Generally the mean is mathematically represented as
=> 
=>
The variance is mathematically represented as
=> 
=>
The standard deviation is mathematically evaluated as
The interval is evaluated as
=> 
=> 
=> 
The binomial random variable x fall into this interval ranges from
- 5 to 5
Generally
![P(6 \le x \le 14) = P(\frac{ x - \mu }{\sigma } \le \frac{14 - 10}{{2.45}} ]-P[ \frac{ x - \mu }{\sigma } \le \frac{6 - 10}{2.45 } ]](https://tex.z-dn.net/?f=P%286%20%5Cle%20x%20%5Cle%2014%29%20%3D%20%20P%28%5Cfrac%7B%20x%20-%20%20%5Cmu%20%7D%7B%5Csigma%20%7D%20%20%5Cle%20%20%5Cfrac%7B14%20-%2010%7D%7B%7B2.45%7D%7D%20%5D-P%5B%20%20%5Cfrac%7B%20x%20-%20%20%5Cmu%20%7D%7B%5Csigma%20%7D%20%20%20%5Cle%20%5Cfrac%7B6%20-%2010%7D%7B2.45%20%7D%20%5D)
![P(6 \le x \le 14) = P(Z \le 1.63 ]-P[ Z \le -1.63 ]](https://tex.z-dn.net/?f=P%286%20%5Cle%20x%20%5Cle%2014%29%20%3D%20%20P%28Z%20%20%5Cle%201.63%20%5D-P%5B%20Z%20%20%5Cle%20-1.63%20%5D)
![P(6 \le x \le 14) = [1- P(Z > 1.63 ]] -[1- P[ Z > -1.63 ]]](https://tex.z-dn.net/?f=P%286%20%5Cle%20x%20%5Cle%2014%29%20%3D%20%20%5B1-%20P%28Z%20%20%3E%201.63%20%5D%5D%20-%5B1-%20P%5B%20Z%20%20%3E%20-1.63%20%5D%5D)
From the z-table
And
=> ![P(6 \le x \le 14) = [1-0.051551] -[1-0.94845]](https://tex.z-dn.net/?f=P%286%20%5Cle%20x%20%5Cle%2014%29%20%3D%20%20%5B1-0.051551%5D%20-%5B1-0.94845%5D)
=>
